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7nadin3 [17]
3 years ago
10

Find the location of A' given that A is (4,5). Translate 1 unit left. The location of A is​

Mathematics
1 answer:
Nady [450]3 years ago
8 0

Answer:

3,5

Step-by-step explanation:

You just move it to the left

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The population of a town was 6,000
Wewaii [24]

Answer: It is expected to increase by 240 people

Step-by-step explanation: 0.04*6000=240

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3 years ago
What would 2 x (x-3) sum be
brilliants [131]

Answer:

2x-6 I think

Step-by-step explanation:

4 0
2 years ago
Shen needs to memorize words on a vocabulary list for german class. he has memorized 12 of the words, which is two-thirds of the
katrin [286]
2/3 of the list = 12

2/3x = 12
x = 12 / (2/3)
x = 12 * 3/2
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3 0
3 years ago
Solve. 90<img src="https://tex.z-dn.net/?f=x" id="TexFormula1" title="x" alt="x" align="absmiddle" class="latex-formula"> = 27.
Irina-Kira [14]

Answer: x≈0.732

Step-by-step explanation:

You need to find the value of the variable "x".

To solve for "x" you need to apply the following property of logarithms:

log(m)^n=nlog(m)

Apply logarithm on both sides of the equation:

90^x=27\\\\log(90)^x=log(27)

Now, applying the property mentioned before, you can rewrite the equation in this form:

xlog(90)=log(27)

Finally, you can apply the Division property of equality, which states that:  

 If\ a=b,\ then\ \frac{a}{c}=\frac{b}{c}

Therefore, you need to divide both sides of the equation by log(90). Finally, you get:

\frac{xlog(90)}{log(90)}=\frac{log(27)}{log(90)}\\\\x=\frac{log(27)}{log(90)}

x≈0.732

7 0
3 years ago
A welder requires 18 hours to do a job. After the welder and an apprentice work on a job for 6 hours, the welder moves to anothe
Dafna1 [17]

Answer:

the apprentice can complete the job in 30 hours by working alone.

Step-by-step explanation:

Given:

Number of hours required to complete a job by welder = 18 hours

Number of hours welder work on job = 6 hours.

Number of hours required by apprentice to complete the job = 14 hours

We need to find Number of hours required to complete a job by apprentice alone.

Solution:

Let Number of hours required to complete a job by apprentice alone be 'a'.

Also let the job completed be = 1

Now we know that ;

Time required on job is equal to sum of Number of hours welder work on job and Number of hours required by apprentice to complete the job.

framing in equation form we get

Time required on job =  6+14 =20\ hrs

Now we can say that;

each has done a fraction of the work so we will add to two fraction as number of hours of work done by Total number of hours required to do the work to complete 1 job.

so we can frame the equation as;

\frac{6}{18}+\frac{20}{a}=1

By reducing the fraction we get;

\frac{1}{3}+\frac{20}{a}=1

Now we will make the denominator common to solve the fraction we get;

\frac{1\times a}{3\times a}+\frac{20\times3}{a\times3}=1\\\\\frac{a}{3a}+\frac{60}{3a}=1

Now denominators are same so we will solve the numerator we get;

\frac{a+60}{3a}=1

Multiplying both side by 3a we get;

\frac{a+60}{3a}\times3a=1\times 3a\\\\a+60=3a

Combining the like terms we get;

3a-a=60\\\\2a=60

Dividing both side by 2 we get;

\frac{2a}{2}=\frac{60}{2}\\\\a=30\ hrs

Hence the apprentice can complete the job in 30 hours by working alone.

4 0
3 years ago
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