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mario62 [17]
3 years ago
6

Recall that the essential matrix E describing the stereo geometry of two calibrated cameras is a function only of the relative r

otation and translational offset between the two cameras. Compute the essential matrix for the following camera configurations.
The Point Grey "Bumblebee" stereo camera is a "simple stereo" system having two cameras side-by-side with their optic axes parallel to each other. The baseline distance between the two cameras is 12 cm.
Compute the values of the 3x3 essential matrix E for this stereo system.

Physics
1 answer:
Mashcka [7]3 years ago
7 0

Answer:

The essential matrix in this case is given by      

         E=[T_{x}]R=\left[\begin{array}{ccc}0&0&0\\0&0&d\\0&-d&0\end{array}\right]

the values of the 3x3 essential matrix E for this stereo system

E=[T_{x}]R=\left[\begin{array}{ccc}0&0&0\\0&0&0.12\\0&-0.12&0\end{array}\right]

Explanation:

The explanation is shown on the first uploaded image

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How does energy transfer by waves differ from energy transfer by moving object
vodomira [7]
Energy transfer by waves: two primary modes = (electromagnetic waves, compression/transverse waves propagating through a medium)

1) electromagnetic waves:

Using a particle model for the wave (photons for light), energy transfer is similar to that by discrete moving object -- particles carry the energy from one place to another in the absence of a medium.

Energy delivery: discrete moving object uses inertia and momentum to transfer the energy from itself to the target. Photons are massless, so the energy delivery mechanism must be different.

2) compression/transverse waves propagating through a medium:

Energy passes through the medium with little to no net flow of the medium itself. In transverse water waves, when the energy wave passes by, to first order, the water particles move in vertical circular paths. This is different from energy transfer by a moving object in that the moving object must displace itself to the target position in order to deliver the energy -- resulting in a net flow of object material.
5 0
3 years ago
Bernie drove home from a vacation in 1.5 hours. He traveled a total distance of 60 miles. What was his average speed in miles pe
mafiozo [28]

Answer: 40

Explanation:

I believe this is correct. I did 60/1.5 to get 40/mph

6 0
4 years ago
Read 2 more answers
Using a mass of 1. 8 g and the volume displaced by the sample, calculate the sample's density. Question 17 options: 0. 17 g/mL 0
LUCKY_DIMON [66]

The sample's density with respect to the volume it displaces is equal to: C. 0. 60 g/mL

<u>Given the following data:</u>

  • Mass = 1.8 grams
  • Initial volume = 20 mL
  • Final volume = 23 mL

To calculate the sample's density:

First of all, we would determine the volume displaced by the sample;

Volume \;displaced = 23-20

Volume displaced = 3 mL

Density can be defined as mass all over the volume of an object. Thus, density is mass per unit volume of an object.

Mathematically, the density of a substance is given by the formula;

Density = \frac{Mass}{Volume}

Substituting the given parameters into the formula, we have;

Density = \frac{1.8}{3}

Density = 0.60 g/mL

Read more: brainly.com/question/18320053

8 0
3 years ago
A ball is launched from ground level at 30 m/s at an angle of 35° above the horizontal. how far does it go before it is at groun
frutty [35]

Answer:

Explanation:

Ignoring air resistance

Initial vertical velocity is 30sin35 = 17.2 m/s

Gravity reduces this velocity to zero in a time of

t = v/g =17.2 / 9.8 = 1.755 s

it takes the same time to come back down to ground level for a total flight time of 2(1.755) = 3.51 s

The horizontal velocity is 30cos35 = 24.57 m/s

the distance traveled horizontally is

d = vt = 24.57(3.51) = 86.298... = 86 m

7 0
2 years ago
2. Can you place three forces of 5g, 6g, and 12g so they are in equilibrium. Justify your answer.
Bond [772]

Answer:

We cannot place three forces of 5g, 6g, and 12g in equilibrium.

Explanation:

Equilibrium means their sum must be zero.

Here the forces are 5g, 6g, and 12g.

For number of forces to be in equilibrium the magnitude of largest vector should be less than sum of the magnitude of other vectors.

Here

        Magnitude of largest force = 12 g

        Sum of magnitudes of other forces = 5g + 6g = 11g

       Magnitude of largest force >   Sum of magnitudes of other forces

So this forces cannot form equilibrium.

We cannot place three forces of 5g, 6g, and 12g in equilibrium.

4 0
3 years ago
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