Energy transfer by waves: two primary modes = (electromagnetic waves, compression/transverse waves propagating through a medium)
1) electromagnetic waves:
Using a particle model for the wave (photons for light), energy transfer is similar to that by discrete moving object -- particles carry the energy from one place to another in the absence of a medium.
Energy delivery: discrete moving object uses inertia and momentum to transfer the energy from itself to the target. Photons are massless, so the energy delivery mechanism must be different.
2) compression/transverse waves propagating through a medium:
Energy passes through the medium with little to no net flow of the medium itself. In transverse water waves, when the energy wave passes by, to first order, the water particles move in vertical circular paths. This is different from energy transfer by a moving object in that the moving object must displace itself to the target position in order to deliver the energy -- resulting in a net flow of object material.
Answer: 40
Explanation:
I believe this is correct. I did 60/1.5 to get 40/mph
The sample's density with respect to the volume it displaces is equal to: C. 0. 60 g/mL
<u>Given the following data:</u>
To calculate the sample's density:
First of all, we would determine the volume displaced by the sample;

Volume displaced = 3 mL
Density can be defined as mass all over the volume of an object. Thus, density is mass per unit volume of an object.
Mathematically, the density of a substance is given by the formula;

Substituting the given parameters into the formula, we have;

Density = 0.60 g/mL
Read more: brainly.com/question/18320053
Answer:
Explanation:
Ignoring air resistance
Initial vertical velocity is 30sin35 = 17.2 m/s
Gravity reduces this velocity to zero in a time of
t = v/g =17.2 / 9.8 = 1.755 s
it takes the same time to come back down to ground level for a total flight time of 2(1.755) = 3.51 s
The horizontal velocity is 30cos35 = 24.57 m/s
the distance traveled horizontally is
d = vt = 24.57(3.51) = 86.298... = 86 m
Answer:
We cannot place three forces of 5g, 6g, and 12g in equilibrium.
Explanation:
Equilibrium means their sum must be zero.
Here the forces are 5g, 6g, and 12g.
For number of forces to be in equilibrium the magnitude of largest vector should be less than sum of the magnitude of other vectors.
Here
Magnitude of largest force = 12 g
Sum of magnitudes of other forces = 5g + 6g = 11g
Magnitude of largest force > Sum of magnitudes of other forces
So this forces cannot form equilibrium.
We cannot place three forces of 5g, 6g, and 12g in equilibrium.