Question

An observant fan at a baseball game notices that the radio commentators have lowered a microphone from their booth to just a few centimeters above the ground. (The microphone is used to pick up sounds from the field.) The fan also notices that the microphone is slowly swinging back and forth like a simple pendulum. Using her digital watch, she finds that 1010 complete oscillations take 20.2s20.2s. How high above the field is the radio booth?

Answer 1

Answer:

The radio booth is 0.993 meters above the field.

Explanation:

The pendulum covers 10 complete oscillations to take 20 s. We need to find the height above the radio booth. The time period of the pendulum is given by :

$T=2\pi \sqrt{\dfrac{L}{g}} \\\\L=(\dfrac{T}{2\pi })^2g\\\\L=(\dfrac{(20/10)}{2\pi })^2\times 9.8\\\\L=0.993\ m$

So, the radio booth is 0.993 meters above the field.