state whether the following changes are physical or chemical for rancidipication fixation of water 2 tearing of paper 3 rusting
1 answer:
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For the 1st order reactions,rate constant (k) is mathematically expressed as
k =
where, t = time
Co = initial conc. of reactant
Ct = conc. of reactant after time 't'
Given: k = <span>2.20 × 10^-5 s-1, t = 2 hours = 7200 s
Therefore, we have
</span>2.20 × 10^-5 =
∴
= 0.06877
∴,
= 1.1716
∴, Ct = 85.35%
Thus, <span>85.35 % of the initial amount of SO2Cl2 will remain after 2.00 hours.</span>
k =
where, t = time
Co = initial conc. of reactant
Ct = conc. of reactant after time 't'
Given: k = <span>2.20 × 10^-5 s-1, t = 2 hours = 7200 s
Therefore, we have
</span>2.20 × 10^-5 =
∴
∴,
∴, Ct = 85.35%
Thus, <span>85.35 % of the initial amount of SO2Cl2 will remain after 2.00 hours.</span>
Explanation:
It is known that equation for ideal gas is as follows.
PV = nRT
The given data is as follows.
Pressure, P = 1500 psia, Temperature, T = = 104 + 460 = 564 R
Volume, V = 2.4 cubic ft, R = 10.73
Also, we know that number of moles is equal to mass divided by molar mass of the gas.
n =
m =
=
= 9.54 lb
Hence, molecular weight of the gas is 9.54 lb.
- We will calculate the density as follows.
d =
=
= 3.975
- Now, calculate the specific gravity of the gas as follows.
Specific gravity relative to air =
=
= 51.96