Answer:
The correct answer is - 9935 years approximately.
Explanation:
Let z be the age in years to be found:
(15300 disintegrations) x (1.0 g / 0.250 g) / (1.84×10^4 disintegrations)
= 3.3260
half life of carbon = (1/2)^(z/5730 yr)
Solve for z
3.3260 = (1/2)^(z/5730)
Take the log of both sides:
log 3.3260 = (z/5730) log (1/2)
log 3.3260 / log (1/2) = z/5730
z = 5730 log 3.3260 / log (1/2)
= 1.73378816*5730
= 9935 years approximately.
A.
Proteins → RNA → DNA
I think..
<span>Hope this helps. c:</span>
Note down the formula below
![\boxed{\sf Mass\%\;of\; element=\dfrac{Mass\:of\:the\: element}{Mass\;of\:the\: compound}\times 100}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20Mass%5C%25%5C%3Bof%5C%3B%20element%3D%5Cdfrac%7BMass%5C%3Aof%5C%3Athe%5C%3A%20element%7D%7BMass%5C%3Bof%5C%3Athe%5C%3A%20compound%7D%5Ctimes%20100%7D)
Mass of the compound
![\\ \sf\longmapsto 15+120=135g](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%2015%2B120%3D135g)
Mass % of Hydrogen:-
![\\ \sf\longmapsto \dfrac{15}{135}\times 100](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cdfrac%7B15%7D%7B135%7D%5Ctimes%20100)
![\\ \sf\longmapsto \dfrac{1}{9}\times 100](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cdfrac%7B1%7D%7B9%7D%5Ctimes%20100)
![\\ \sf\longmapsto 11.1\%](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%2011.1%5C%25)
Mass % of Oxygen:-
![\\ \sf\longmapsto \dfrac{120}{135}\times 100](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cdfrac%7B120%7D%7B135%7D%5Ctimes%20100)
![\\ \sf\longmapsto \dfrac{8}{9}\times 100](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cdfrac%7B8%7D%7B9%7D%5Ctimes%20100)
![\\ \sf\longmapsto 88.9\%](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%2088.9%5C%25)