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3 years ago

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Chemistry

2 answers:

Serhud [2]3 years ago

8 0

Answer: In two molecules of carbon dioxide (2CO2), there are _____.

two atoms of carbon

four atoms of oxygen

riadik2000 [5.3K]3 years ago

7 0

Two atoms of carbon and four atoms of oxygen (please give me brainliest

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you rent a car in Germany with a gas mileage rating of 12.8km/L. What is its rating in miles per gallon?

Oksi-84 [34.3K]

so one liter is about 2. something gallons so at 12.8 km/l you would get about 30 mpg which is insane but yeah

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3 years ago

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Select True or False: Pi bonds are covalent bonds in which the electron density is concentrated above and below a plane containi

anzhelika [568]

Answer:

True

Explanation:

In pi bonds, the electron density concentrates itself between the atoms of the compound but are present on either side of the line joining the atoms. Electron density is found above and below the plane of the line joining the internuclear axis of the two atoms involved in the bond.

Pi bonds usually occur by sideways overlap of atomic orbitals and this leads to both double and triple bonds.

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3 years ago

Let us write the appropriate equilibria and associate the correction <img src="https://tex.z-dn.net/?f=K_b" id="TexFormula1" tit

rosijanka [135]

Explanation:

The relation between $K_a\&K_b$ is given by :

$K_w=K_a\times K_b$

Where :

$K_w=1\times 10^{-14}$ = Ionic prodcut of water

The value of the first ionization constant of sodium sulfite = $K_{a1}=1.4\times 10^{-2}$

The value of $K_{b1}$ :

$1\times 10^{-14}=1.4\times 10^{-2}\times K_{b1}$

$K_{b1}=\frac{1\times 10^{-14}}{1.4\times 10^{-2}}=7.1\times 10^{-13}$

The value of the second ionization constant of sodium sulfite = $K_{a2}=6.3\times 10^{-8}$

The value of $K_{b2}$ :

$1\times 10^{-14}=6.3\times 10^{-8}\times K_{b1}$

$K_{b1}=\frac{1\times 10^{-14}}{6.3\times 10^{-8}}=1.6\times 10^{-7}$

3 0

3 years ago

Without consulting Appendix B, arrange each group in order of decreasing standard molar entropy (S°). Explain.(b) NO₂(g), NO(g),

denpristay [2]

The decreasing order of standard molar entropy (S°) is as follow:

NO₂(g) > NO(g) > N₂(g)

<h3>What is Entropy? </h3>

Entropy is defined as the randomness of the particle. It depends on temperature and pressure or number of particle per unit volume.

It is directly proportional to the temperature and pressure of the gas.

<h3>What is Standard Molar Entropy? </h3>

The standard molar entropy is defined as the entropy content of the one mole of pure substance at the standard state of temperature and pressure of interest.

The standard molar entropy is also defined as the total amount of entropy which 1 mole of the substance acquire, as it is brought from 0K to standard conditions of temperature and pressure.

The standard molar entropy depends on the molas mass of atom, molecules or compound.

N₂ has lower standard molar entropy. This can be explained as this molecule consist of same atom.

While, Complexity increases from NO to NO₂(g). Therefore, the standard molar entropy of NO₂(g) is greater than NO.

Thus, we concluded that the decreasing order of standard molar entropy (S°) is as follow:

NO₂(g) > NO(g) > N₂(g)

learn more about standard molar entropy:

brainly.com/question/15908262

#SPJ4

8 0

1 year ago

Hydrogen bromide is found in volcanic gas. What is the chemical formula for<br> this compound?

ruslelena [56]

Answer:

Hydrogen bromide, anhydrous appears as a colorless gas with a pungent irritating odor. Corrosive. Heavier than air. Prolonged exposure to fire or intense heat may result in the violent rupture and rocketing of the container. Long-term exposure to low concentrations or short-term exposure to high concentrations can result in adverse health effects from inhalation. Used to make other chemicals and as a catalyst in the manufacture of chemicals. Rate of onset: Immediate Persistence: Minutes to hours Odor threshold: 2 ppm Source/use/other hazard: Chemical manufacturing industry; very corrosive.

Explanation:

HBr

3 0

3 years ago

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