Answer:
1.8 x 10²⁴ atoms Ag
Explanation:
You can find the amount of silver (Ag) atoms by multiplying the moles by Avogadro's number. It is important to arrange the conversion in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 2 sig figs to match the sig figs of the given value.
Avogadro's Number:
6.022 x 10²³ atoms = 1 mole
3.0 moles Ag 6.022 x 10²³ atoms
---------------------- x -------------------------------- = 1.8 x 10²⁴ atoms Ag
1 mole
The British Petroleum (bp's) effort to close the blowout preventer and install a containment dome following an explosion on the deepwater horizon drilling rig is an example of <u>regulatory policy </u>change.
The deepwater horizon drilling rig is a semi-submersible, transportable, floating, flexibly oriented drilling rig that could work in sea depths of up to 10,000 feet which is approximately 3,000 meters.
During the explosion that occurred in April 2010, British Petroleum made several efforts to contain the damages made and to prevent further outbreaks of disasters.
Part of the changes was shifting from a blowout preventer that has a specialized valve to seal, manage, and monitor oil and gas wells in order to prevent blowouts to a containment dome (a crucial component of a system meant to control an oil well's underwater blowout).
Therefore, we can conclude that the British Petroleum (bp's) effort to close the blowout preventer and install a containment dome following an explosion on the deepwater horizon drilling rig is an example of <u>regulatory policy </u>change.
Learn more about deepwater horizon drilling rig here:
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Molar mass KCl = <span>74.5513 g/mol
Number of moles:
21.9 / 74.5513 => 0.293 moles
Volume = 869 mL / 1000 => 0.869 L
Molarity = moles / Volume
Molarity = 0.293 / 0.869
=> 0.337 M</span>
Below is the list of enthalpies of formation of the compounds involved in the chemical reaction.
HCl: -92.3 kJ/mol
H2: 0
Cl2: 0
Both H2 and Cl2 do not have enthaply of formation because they are pure substances.
Since, in the reaction there are 2 moles of HCl,
Enthalphy of formation = enthalpy of products - enthalphy of reactant/s
= 0 - (-92.3)(2) = +184.6 kJ
Hence, the answer is the first choice.
