This separation technique is a 4-step procedure. First, add H₂SO₄ to the solution. Because of common ion effect, BaSO₄ will not react, only Mg(OH)₂.
Mg(OH)₂ + H₂SO₄ → MgSO₄ + 2 H₂O
The aqueous solution will now contain MgSO₄ and BaSO₄. Unlike BaSO₄, MgSO₄ is soluble in water. So, you filter out the solution. You can set aside the BaSO₄ on the filter paper. To retrieve Mg(OH)₂, add NaOH.
MgSO₄ + 2 NaOH = Mg(OH)₂ + Na₂SO₄
Na₂SO₄ is soluble in water, while Mg(OH)₂ is not. Filter this solution again. The Mg(OH)₂ is retrieved in solid form on the filter paper.
Answer:
7.22L
Explanation:
At Stp T2 = 273K and P2 is 1 atm
So we have the following data
V1 =10L. P1=650mmHg(0.855atm)
V2 =V2. P2 = 1 atm
T1=50°c (323K) T2 =273K
Hence from the combined gas law
P1xV1 /T1 =P2xV2/T2
0.855x10/323 =1xV2 /273
8.55/323 =V2 /273
V2 = 8.55x273 /323
V2 = 7.226 L
Answer:
exothermic process because the process of association of oxygen and hydrogen is taking place..
Answer:
C
Explanation:
it's always colder at night and close to night especially near water and that's when wind tends to blow the most
