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kirill [66]
3 years ago
14

Suppose you have a mixture of solid mg(oh)2 and baso4, how do you separate the mixture

Chemistry
1 answer:
Step2247 [10]3 years ago
5 0
This separation technique is a 4-step procedure. First, add H₂SO₄ to the solution. Because of common ion effect, BaSO₄ will not react, only Mg(OH)₂.

Mg(OH)₂ + H₂SO₄ → MgSO₄ + 2 H₂O

The aqueous solution will now contain MgSO₄ and BaSO₄. Unlike BaSO₄, MgSO₄ is soluble in water. So, you filter out the solution. You can set aside the BaSO₄ on the filter paper. To retrieve Mg(OH)₂, add NaOH.

MgSO₄ + 2 NaOH = Mg(OH)₂ + Na₂SO₄

Na₂SO₄ is soluble in water, while Mg(OH)₂ is not. Filter this solution again. The Mg(OH)₂ is retrieved in solid form on the filter paper.
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When the volume of a gas is changed from 11.5 cm3 to ?cm the temperature will change from 415 K to 200 K
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Assuming that the gas acts like an ideal gas, we can calculate for the final volume using the ideal gas law:

PV = nRT

Where P = pressure, V = volume, n = number of moles, R = gas constant, and T = temperature

Assuming that P, n, and R are constant throughout the process, we can define another constant K:

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Equating the initial and final states:

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Substituting the given values:

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