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kirill [66]
2 years ago
14

Suppose you have a mixture of solid mg(oh)2 and baso4, how do you separate the mixture

Chemistry
1 answer:
Step2247 [10]2 years ago
5 0
This separation technique is a 4-step procedure. First, add H₂SO₄ to the solution. Because of common ion effect, BaSO₄ will not react, only Mg(OH)₂.

Mg(OH)₂ + H₂SO₄ → MgSO₄ + 2 H₂O

The aqueous solution will now contain MgSO₄ and BaSO₄. Unlike BaSO₄, MgSO₄ is soluble in water. So, you filter out the solution. You can set aside the BaSO₄ on the filter paper. To retrieve Mg(OH)₂, add NaOH.

MgSO₄ + 2 NaOH = Mg(OH)₂ + Na₂SO₄

Na₂SO₄ is soluble in water, while Mg(OH)₂ is not. Filter this solution again. The Mg(OH)₂ is retrieved in solid form on the filter paper.
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Nitrogen monoxide, NO, is formed in automobile exhaust by the reaction of nitrogen and oxygen in the air: N2 (g) + O2 (g) ↔ NO (
Solnce55 [7]

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The equilibrium concentration of NO is 0.001335 M

Explanation:

Step 1: Data given

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N2(g) + O2(g) ↔ 2NO(g)

Step 3:  Concentration at the equilibrium

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3 years ago
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