Answer:
pHe = 3.2 × 10⁻³ atm
pNe = 2.5 × 10⁻³ atm
P = 5.7 × 10⁻³ atm
Explanation:
Given data
Volume = 1.00 L
Temperature = 25°C + 273 = 298 K
mHe = 0.52 mg = 0.52 × 10⁻³ g
mNe = 2.05 mg = 2.05 × 10⁻³ g
The molar mass of He is 4.00 g/mol. The moles of He are:
0.52 × 10⁻³ g × (1 mol / 4.00 g) = 1.3 × 10⁻⁴ mol
We can find the partial pressure of He using the ideal gas equation.
P × V = n × R × T
P × 1.00 L = 1.3 × 10⁻⁴ mol × (0.082 atm.L/mol.K) × 298 K
P = 3.2 × 10⁻³ atm
The molar mass of Ne is 20.18 g/mol. The moles of Ne are:
2.05 × 10⁻³ g × (1 mol / 20.18 g) = 1.02 × 10⁻⁴ mol
We can find the partial pressure of Ne using the ideal gas equation.
P × V = n × R × T
P × 1.00 L = 1.02 × 10⁻⁴ mol × (0.082 atm.L/mol.K) × 298 K
P = 2.5 × 10⁻³ atm
The total pressure is the sum of the partial pressures.
P = 3.2 × 10⁻³ atm + 2.5 × 10⁻³ atm = 5.7 × 10⁻³ atm
Not quite sure what you're asking, but I think what you're looking for is 'Native Species'.
Answer:A
Explanation:I hope I’m right
Answer:
= 3.56 atm
Explanation:
Using Boyle's law which states that the volume of a given mass of gas is inversely proportional to the pressure and Charles law states the volume of a given mass of gas is directly proportional to the temperature.
P1/T1 = P2/T2
P1 = 3.1 atm, T1 = 100'C = 100+273 = 373K
T2 = 155'C = 155 + 273 = 428K
3.1/ 373 = P2 / 428
Cross multiply
373 × P2 = 3.1 × 428
373×P2 = 1326.8
Divide both sides by 373
P2 = 1326.8 ÷ 373
P2 = 3.56 atm
I hope this was helpful, please mark as brainliest
