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3 years ago

In the inequality, what are all the possible values of x?

Mathematics

1 answer:

Marat540 [252]3 years ago

7 0

Answer:

B) $\displaystyle x ≤ 0$

Step-by-step explanation:

2(x + 12) − 16 ≤ 8

$\displaystyle \frac{2(x + 12)}{2} ≤ \frac{24}{2} \\ \\ x + 12 ≤ 12 \\ \\ x ≤ 0$

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2 years ago

a student Miss 10 problems on an English test and received a grade of 44%. If all the problems were of equal value, how many pro

eimsori [14]

Answer:

Rounded to the nearest integer, the test had 18 problems in all.

Step-by-step explanation:

Given that a student missed 10 problems on an English test and received a grade of 44%, if all the problems were of equal value, to determine how many problems were on the test the following calculation must be performed:

100 - 44 = 56

56 = 10

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100 x 10/56 = X

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2 years ago

Find f(-3) if f(x) = x2.

Vesna [10]

Answer:

f(-3) = 9

Step-by-step explanation:

Step 1: Define

f(-3) = x = -3

f(x) = x²

Step 2: Substitute and Evaluate

f(-3) = (-3)²

f(-3) = 9

7 0

2 years ago

Peter and his four brothers combined all of their money to buy a video game. If 30% of the total money is Peter's, and $12.00 of

kari74 [83]

Answer:

$20.00

Step-by-step explanation:

t represents the total amount

0.25t = 5.00

Can you solve for t and answer?

Or logically

Peter's $5.00 is 1/4 (25%) of the total.

Therefore 4/4 is $20.00

6 0

1 year ago

Read 2 more answers

Question regarding logarithms.

Eddi Din [679]

$5^{x-2}-7^{x-3}=7^{x-5}+11\cdot5^{x-4}\\\\5^{x-2}-7^{x-2-1}=7^{x-2-3}+11\cdot5^{x-2-2}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\5^{x-2}-\dfrac{7^{x-2}}{7^1}=\dfrac{7^{x-2}}{7^3}+11\cdot\dfrac{5^{x-2}}{5^2}\\\\5^{x-2}-\dfrac{1}{7}\cdot7^{x-2}=\dfrac{1}{343}\cdot7^{x-2}+\dfrac{11}{25}\cdot5^{x-2}\\\\-\dfrac{1}{7}\cdot7^{x-2}-\dfrac{1}{343}\cdot7^{x-2}=\dfrac{11}{25}\cdot5^{x-2}-5^{x-2}\\\\\left(-\dfrac{1}{7}-\dfrac{1}{343}\right)\cdot7^{x-2}=\left(\dfrac{11}{25}-1\right)\cdot5^{x-2}$

$\left(-\dfrac{49}{343}-\dfrac{1}{343}\right)\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\\\\-\dfrac{50}{343}\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\qquad\text{multiply both sides by}\ \left(-\dfrac{25}{14}\right)\\\\\dfrac{50\cdot25}{343\cdot14}\cdot7^{x-2}=5^{x-2}\qquad\text{divide both sides by}\ 7^{x-2}\\\\\dfrac{25\cdot25}{343\cdot7}=\dfrac{5^{x-2}}{7^{x-2}}\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}$

$\dfrac{5^2\cdot5^2}{7^3\cdot7}=\left(\dfrac{5}{7}\right)^{x-2}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{5^4}{7^4}=\left(\dfrac{5}{7}\right)^{x-2}\\\\\left(\dfrac{5}{7}\right)^4=\left(\dfrac{5}{7}\right)^{x-2}\iff x-2=4\qquad\text{add 2 to both sides}\\\\\boxed{x=6}$

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3 years ago

Read 2 more answers