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Elena-2011 [213]
2 years ago
11

PLEASE HELP ME!

Chemistry
1 answer:
uysha [10]2 years ago
8 0

Answer:

1) reduction

2) zero

Explanation:

Let us look at the definition of oxidation and reduction in a nutshell.

Oxidation is electron loss(oxidation number is increased)

Reduction is electron gain(oxidation number is decreased)

With the above definitions in mind let us look again at the equation in question 1:

Br2 + 2e- → 2Br-

We can see that the bromine molecule gained two electrons. Oxidation number decreased from zero on the left hand side of the reaction equation to -1 on the right hand side of the reaction equation hence the equation represents a reduction half equation.

For question 2, silver was displaced from its salt. On the left hand side of the reaction equation, silver had an oxidation number of +2. But remember than one of the riles for determining oxidation number of species is that the oxidation number of an uncombined element is zero. Hence, the oxidation number of silver element on the right hand side of the reaction equation is zero.

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43.8 kJ

<h3>Explanation</h3>

There are two electrodes in a voltaic cell. Which one is the anode?

The lithium atom used to have no oxygen atoms when it was on the reactant side. It gains two oxygen atoms after the reaction. It has gained more oxygen atoms than the manganese atom. Gaining oxygen is oxidation. As a result, lithium is being oxidized.

Oxidation takes place at the anode of a cell. Therefore, the anode of this cell is made of lithium.

Lithium has an atomic mass of 6.94. Each gram of Li would contain 1/6.94 = 0.144 moles of Li atoms. Each Li atom loses one electron in this cell. Therefore, the number of electron transferred, <em>n</em>, equals 0.144 moles for each gram of the anode.

Let w_\text{max} represents the electrical energy produced.

w_\text{max} = n \cdot F \cdot E_\text{cell}, where

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<em>n </em>= 0.144 mol, as shown above, and

<em>F </em>= 96.486 kJ / (\text{V} \cdot \text{mol} \; \text{e}^{-}).

Therefore,

w_\text{max} = n \cdot F \cdot E\\\phantom{w_\text{max}} = 0.144 \times 96.486 \times 3.15 \\\phantom{w_\text{max}} = 43.8 \; \text{kJ}.

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