At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the partial pressure of He would give a solubility of 0.200 M.
<h3>What is Henry's Law ?</h3>
Henry's Law is a gas law states that at a constant temperature the amount of gas that dissolved in a liquid is directly proportional to the partial pressure of that gas.
<h3>What is relationship between Henry's Law constant and Solubility ?</h3>
The solubility of gas is directly proportional to partial pressure.
It is expressed as:

where,
= Solubility of gas
= Henry's Law constant
= Partial pressure of gas
Now put the values in above expression we get

0.080M =
× 1.7 atm

= 0.047 M/atm
Now we have to find the partial pressure of He

0.200 M = 0.047 M/atm × 

= 4.25 atm
Thus from the above conclusion we can say that At a particular temperature, the solubility of He in water is 0.080 M when the partial pressure is 1.7 atm. 4.25 atm is the partial pressure of He would give a solubility of 0.200 M.
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Answer:
See the attached file for the structure.
Explanation:
Find attached for the explanation
Answer:
see notes below
Explanation:
The mole is the mass of substance containing 1 Avogadro's Number of particles. That is, 1 mole substance = 1 formula weight. For elements, 1 mole weight is equal to the atomic weight expressed as grams. For molecules, 1 mole weight is equal to the molecular weight expressed as grams.
1 mole = 1 formula weight
<u>Moles to Grams and Grams to Moles</u>
Grams => Moles
Given grams, moles = mass given / formula weight
*Ask the question => How many formula weights are there in the given mass? => Results is always moles.
Moles => Grams
Given moles, grams = moles given X formula weight
*Summary
Grams to Moles => divide by formula weight
Moles to Grams => multiply by formula weight
1 mole of any gas under STP has volume 22.4 L
So 2.50 moles of any gas ( including oxygen)
2.50 mol *(22.4L/1 mol)=56.0 L