Answer:
874.89 mmHg
Explanation:
Using the combined gas law equation as follows:
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (mmHg)
P2 = final pressure (mmHg)
V1 = initial volume (L)
V2 = final volume (L)
T1 = initial temperature (K)
T2 = final temperature (K)
Based on the information provided in this question;
P1 = 950 mm Hg
P2 = ?
V1 = 25 L
V2 = 30 L
T1 = 155°C = 155 + 273 = 428K
T2 = 200°C = 200 + 273 = 473K
Using P1V1/T1 = P2V2/T2
950 × 25/428 = P2 × 30/473
23750/428 = 30P2/473
55.49 = 0.063P2
P2 = 55.49 ÷ 0.063
P2 = 874.89 mmHg
Answer:
Hey there!
The volume of the box would be 45(7)(15), or 4725 cm^3.
The density of any object is the mass divided by volume. Thus, the density of the water would be 14/2, or 7 g/cm^3.
Let me know if this helps :)
D.
The volume of water in a graduated cylinder
should be read at the bottom of the curve of the meniscus.
Answer:
There is 18.8% lithium by mass in second sample
Explanation:
Both the two samples are pure lithium carbonate. So % lithium by mass will be same in both samples. This can be proved mathematically as follows-
Let's assume weight of first sample is x g
So, 100 g of sample contains 18.8 g of lithium
Hence, x g of sample contains 
g of lithium
Now, the second sample has weight equal to 2x g
So, 2x g of sample contains 
g of lithium
So, % lithium by mass in second sample = 
% = 18.8%
