Ground state of Al is 1s²2s²2p⁶3s²3p¹.
Exited state of Al is 1s²2s²2p⁶3s¹3p².
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Answer:</h3>
Ni + Pb(NO₃)₂ → Ni(NO₃)₃ + Pb
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Explanation:</h3>
We are required to write a balanced equation from the word equation;
- Nickel reacts with lead nitrate (II) to produce nickel(III) nitrate and lead
- The equation will be written by writing the symbols of the reactants and products.
That is;
Ni + Pb(NO₃)₂ → Ni(NO₃)₃ + Pb
We then balance the equation;
- To balance the equation, we put appropriate coefficients on reactants and products, so that the number of atoms of each element is equal on both sides of the equation.
- Thus, the balanced equation will be;
2Ni + 3Pb(NO₃)₂ → 2Ni(NO₃)₃ + 3Pb
Answer:
yes it is and sometimes it's not
There are two N≡N bonds and three H–H bonds are in reactants.
Given:
The reaction between nitrogen gas and hydrogen gas.
To find:
Bonds on the reactant side
Solution:
Reactants in the reaction = 
The bond between nitrogen atoms in single 
molecule = N≡N (triple bond)
Then in two molecules = 2 N≡N (triple bonds)
The bond between hydrogen atoms in single 
molecule = H-H (single bond)
Then in three molecules = 3 H-H (single bonds)
Product in the reaction =
The bonds between nitrogen and hydrogen atoms in single molecule = 3 N-H (single bond)
Then in two molecules = 6 N-H (single bonds)
So, there are two N≡N bonds and three H–H bonds are in reactants.
Learn more about reactants and products here:
brainly.com/question/21517037?referrer=searchResults
brainly.com/question/20602904?referrer=searchResults
Answer:
ΔH0reaction = [ΔHf0 CO2(g)] - [ΔHf0 CO(g) + ΔHf0 O2(g)]
Explanation:
Chemical equation:
CO + O₂ → CO₂
Balanced chemical equation:
2CO + O₂ → 2CO₂
The standard enthalpy for the formation of CO = -110.5 kj/mol
The standard enthalpy for the formation of O₂ = 0 kj/mol
The standard enthalpy for the formation of CO₂ = -393.5 kj/mol
Now we will put the values in equation:
ΔH0reaction = [ΔHf0 CO2(g)] - [ΔHf0 CO(g) + ΔHf0 O2(g)]
ΔH0reaction = [-393.5 kj/mol] - [-110.5 kj/mol + 0]
ΔH0reaction = [-393.5 kj/mol] - [-110.5 kj/mol]
ΔH0reaction = -283 kj/mol
