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lianna [129]
4 years ago
7

A capacitor has 10 V initially across and it is instantaneously connected to a resistor. What is the voltage across the capacito

r after one time constant?
Physics
1 answer:
viva [34]4 years ago
7 0

Answer:

3.69 V

Explanation:

By connecting across the resistor, the capacitor starts discharging.

The voltage across the capacitor when discharging is given by

V = V_0e^{-t/T}

V is the voltage across it at time t,

V_0 is the initial voltage when fully charged,

T is the time constant

After one time constant, t = T. Then

V = V_0e^{-T/T}= 0.369V_0

From the question, V_0 =10 \text{ V}

V = 10\text{ V}\times0.369 = 3.69 \text{ V}

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Explanation:

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the act of inferring (to derive by reasoning). Observation = an act or instance of noticing or perceiving.

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5 0
3 years ago
a 40 kilogramstudent runs up a staircase to a floor that is 5.0 meters higher than her starting point in 7.0 seconds. the studen
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When she reaches the top, she has more potential energy than she had at the bottom.

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3 0
3 years ago
When the tympanic membrane vibrates with the same frequency as the incoming sound waves it is known asamplitude.pitch.hertz.reso
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4 0
3 years ago
Two objects, Object A and Object B, need to be identified. Object A's index of refraction is determined to be 1.77, and Object B
Slav-nsk [51]

The correct answer is

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4 0
4 years ago
Read 2 more answers
A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surfac
Lemur [1.5K]

Answer:

a)   v = 0.9167 m / s,  b)  A = 0.350 m,  c)  v = 0.9167 m / s, d)  A = 0.250 m

Explanation:

a) to find the velocity of the wave let us use the relation

          v = λ f

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           λ = x

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the period is the time for the wave to repeat itself, in this case t = 3.00 s corresponds to half a period

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we substitute

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c) The horizontal speed of the traveling wave (waves) is independent of the vertical oscillation of the particles, therefore the speed is the same

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d) the amplitude is

           A = 0.500 / 2

           A = 0.250 m

4 0
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