All categories

3 years ago

How may parent/s is/ are involved in axesual reproducation?

Physics

1 answer:

Tju [1.3M]3 years ago

5 0

Answer:

One parent is involved.

Explanation:

Since in asexual reproduction, the offspring formed will be having the same characteristics or features as of those of the parent.

You might be interested in

Air as an ideal gas enters a diffuser operating at steady state at 5 bar, 280 K with a velocity of 510 m/s. The exit velocity is

Nataly [62]

Answer:

Explanation:

Calculating the exit temperature for K = 1.4

The value of $c_p$ is determined via the expression:

$c_p = \frac{KR}{K_1}$

where ;

R = universal gas constant = $\frac{8.314 \ J}{28.97 \ kg.K}$

k = constant = 1.4

$c_p = \frac{1.4(\frac{8.314}{28.97} )}{1.4 -1}$

$c_p= 1.004 \ kJ/kg.K$

The derived expression from mass and energy rate balances reduce for the isothermal process of ideal gas is :

$0=(h_1-h_2)+\frac{(v_1^2-v_2^2)}{2}$ ------ equation(1)

we can rewrite the above equation as :

$0 = c_p(T_1-T_2)+ \frac{(v_1^2-v_2^2)}{2}$

$T_2 =T_1+ \frac{(v_1^2-v_2^2)}{2 c_p}$

where:

$T_1 = 280 K \\ \\ v_1 = 510 m/s \\ \\ v_2 = 120 m/s \\ \\c_p = 1.0004 \ kJ/kg.K$

$T_2= 280+\frac{((510)^2-(120)^2)}{2(1.004)} *\frac{1}{10^3}$

$T_2 = 402.36 \ K$

Thus, the exit temperature = 402.36 K

The exit pressure is determined by using the relation: $\frac{T_2}{T_1} = (\frac{P_2}{P_1})^\frac{k}{k-1}$

$P_2=P_1(\frac{T_2}{T_1})^\frac{k}{k-1}$

$P_2 = 5 (\frac{402.36}{280} )^\frac{1.4}{1.4-1}$

$P_2 = 17.79 \ bar$

Therefore, the exit pressure is 17.79 bar

7 0

3 years ago

How do you know when electric current is flowing in a lightbulb circuit?

daser333 [38]

The direction of an electric current is by convention the direction in which a positive charge would move. Thus, the current in the external circuit is directed away from the positive terminal and toward the negative terminal of the battery. Electrons would actually move through the wires in the opposite direction.

7 0

3 years ago

On the same spring day, a station near the equator has a surface temperature of 25°C, 15°C higher than the middle-latitude city

DedPeter [7]

Answer:

The air temperature at the tropopause is - 79 °C

Explanation:

We know that a station near the equator has a surface temperature of 25°C

Vertical soundings reveal an environmental lapse rate of 6.5 °C per kilometer.

The tropopause is encountered at 16 km.

In order to find the air temperature at the tropopause we are going to deduce a linear function for the temperature at the tropopause.

This linear function will have the following structure :

$f(x)=ax+b$

Where '' $a$ '' and '' $b$ '' are real numbers.

Let's write $T(x)$ to denote the temperature '' T '' in function of the distance

'' x '' ⇒

$T(x)=ax+b$

We can reorder the function as :

$T(x)=b+ax$ (I)

Now, at the surface the value of '' $x$ '' is 0 km and the temperature is 25°C so in the function (I) we write :

$T(0)=25=b+a(0)$ ⇒ $b=25$ ⇒

$T(x)=25+ax$ (II)

In (II) the value of '' $a$ '' represents the change in temperature per kilometer.

Because the temperature decrease with the height this number will be negative and also a data from the question ⇒

$T(x)=25-(6.5)x$ (III)

In (III) we deduced the linear equation. The last step is to replace by $x=16$ in (III) ⇒

$T(16)=25-(6.5)(16)=-79$

The air temperature at the tropopause is - 79 °C

6 0

3 years ago

Joe noted that the temperature in his aquarium dropped overnight. He concluded that thermal energy moved from the aquarium to th

alukav5142 [94]

Answer:

validate

Explanation:

Law of Conservation of energy

According to the law of conservation of energy, energy of a body or a system gets transferred to another system as different energy. We cannot create energy nor we can destroy energy. Energy is always transformed into other forms of energy.

In the context, Joe noticed that the aquarium's temperature dropped during the night and he concluded that according to the law of conservation of energy, the energy of the aquarium in terms of thermal energy is being transferred to the surrounding air.

This is because the aquarium is considered to be an open system where energy can come in and move out.

Hence Joe's statement is valid.

5 0

3 years ago

Read 2 more answers

In an a.c generator, there are rings used. What are there names and how are they adapted to reversing current.

djyliett [7]

Answer:

In an a.c generator, slip rings are used.

Adaptation: They are not directly connected directly to carbon brushes, hence donot come into contact when the rectangular coil rotates.

Explanation:

$.$