Answer:
a) 0.723 m²
b) 2000V
Explanation:
Given that
Thickness of the capacitor, d = 0.08*10^-3 m
Dielectric constant of the capacitor, k = 2.5
Dielectric strength of the capacitor, E = 50*10^6
Capacitance of the capacitor, C = 0.2*10^-6
Permittivity of free space, E• = 8.85*10^-12
a)
The area, A is given by the formula
A = (C * d) / (k * E•)
A = (0.2*10^-6 * 0.08*10^-3) / (2.5 * 8.85*10^-12)
A = 1.6*10^-11 / 2.213*10^-11
A = 0.723 m²
b)
Potencial difference, V is given by the formula
V = E * d
V = 1/2 * 50*10^6 * 0.08*10^-3
V = 1/2 * 4000
V = 2000 V
Answer:
Here Are Some Tanning Bed Tips For Beginners To Help You Get The Most .Knowing your skin type before you tan can help you to do so safely and help . If you want to ensure you get a quality tan, you first need to be certain your . Obviously, if you wear a bathing suit, you'll get tan lines from the suit. Apply indoor tanning lotion evenly in a circular motion and over all areas of the body. Using the right skin care products is the best way to extend the life of your tan. Note that lotions not made for indoor tanning can cause damage to tanning beds and don't help develop your tan. So what (if anything) should you wear? There are a lot of different views on this particular question, and it all comes down to one very simple answer: wear whatever you are comfortable in. If you wear your bathing suit every time, you will have tan lines that reflect that, but that's your choice.
Explanation:
If a particle undergoes simple harmonic motion with an amplitude of 0.21 meters, this means that the maximum displacement of the particle from its resting position is 0.21. For one period, it traveled from its starting position which is twice the amplitude and then back to its original position which is another distance that is twice the amplitude as well. Therefore, the total distance it traveled is 2*amplitude + 2*amplitude = 2*0.21 + 2*0.21 = 0.42 + 0.42 = 0.84 meters.
Answer:
4.0 m/s
Explanation:
The motion of the diver is the motion of a projectile: so we need to find the horizontal and the vertical component of the initial velocity.
Let's consider the horizontal motion first. This motion occurs with constant speed, so the distance covered in a time t is
where here we have
d = 3.0 m is the horizontal distance covered
vx is the horizontal velocity
t = 1.3 s is the duration of the fall
Solving for vx,
Now let's consider the vertical motion: this is an accelerated motion with constant acceleration g=9.8 m/s^2 towards the ground. The vertical position at time t is given by
where
h = 4.0 m is the initial height
vy is the initial vertical velocity
We know that at t = 1.3 s, the vertical position is zero: y = 0. Substituting these numbers, we can find vy
So now we can find the magnitude of the initial velocity:
