Answer:
U = 9.1 m/s
Explanation:
from the question we are given the following
time (t) = 1.8 s
angle = 23 degrees
acceleration due to gravity (g) = 9.8 m/s^{2}
let us first calculate the initial velocity (u) which too the first ball to its maximum height from the equation below
v = u + 0.5at
- The final velocity (v) is zero since the ball comes to rest
- The time (t) it takes to get to the maximum height would be half the time it is in the air, t = 0.5 x 1.8 = 0.9
therefore
0 = u - (0.5 x 9.8 x 0.9)
u = 7.9 m/s
for the second ball to get to the maximum height of the first ball, the vertical component of its initial velocity (U) must be the same as the initial velocity of the first ball. therefore
U sin 60 = 7.9
U = 7.9 ÷ sin 60
U = 9.1 m/s
The answer is base ball because you run and slide in soccer and you run and slide in rugby. You also hit a Ball in soccer and you hit a ball in rugby.
Answer:
Im not sure who you are talking about, but if you are talking about Dominic Raab, well, he failed to make a crucial phone call to seek urgent help airlifting translators out of Afghanistan. if you are not talking about this Dominic, then please add more information to your question.
Answer:
As = 7.33 [m/s]
Explanation:
To solve this problem we must use the definition of the average speed, which is equal to the relationship between the distance over time.
As = x/t
where:
As = average speed [m/s]
x = distance = 132 [m]
t = time = 18 [s]
As = 132/18
As = 7.33 [m/s]
For the heart rate :
n = number of heat beats = 36
t = time taken to measure = 30 s = 30/60 min = 0.5 min (since 1 min = 60 sec)
R = heart rate
Heart rate is given as
inserting the values
R = 72 min⁻¹
For uncertainty :
Δn = uncertainty in number of heat beats = ± 2
Δt = uncertainty in time taken = ± 0.4 s = ± 0.4/60 min = ± 0.0067 min (since 1 min = 60 sec)
ΔR = uncertainty in heart rate
uncertainty in Heart rate is given as
inserting the values
ΔR = ± 4.96 min⁻¹