Answer: D. New data must be found to support it
When a theory is disproved by other further evidence, it is just proper to look for new data to support the theory until it is proven otherwise. It cannot be considered a failure right away but cannot be part of the scientifi knowledge too and more not to become a law.
There are 0.566 moles of carbonate in sodium carbonate.
<h3>CALCULATE MOLES:</h3>
- The number of moles of carbonate (CO3) in sodium carbonate (Na2CO3) can be calculated by dividing the mass of carbonate in the compound by the molar mass of the compound.
- no. of moles of CO3 = mass of CO3 ÷ molar mass of Na2CO3
- Molar mass of Na2CO3 = 23(2) + 12 + 16(3)
- = 46 + 12 + 48 = 106g/mol
- mass of CO3 = 12 + 48 = 60g
- no. of moles of CO3 = 60/106
- no. of moles of CO3 = 0.566mol
- Therefore, there are 0.566 moles of carbonate in sodium carbonate.
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1.39 g HCl
Explanation:
The balanced chemical equation for this reaction is given by
Zn(<em>s</em>) + 2HCl(<em>aq</em>) ---> ZnCl2(<em>aq</em>) + H2(<em>g</em>)
Convert the # of grams of Zn to moles:
1.25 g Zn × (1 mol Zn/65.38 g Zn) = 0.0191 mol Zn
Use the molar ratio to find the # of moles of HCl needed to react completely with the given amount of Zn:
0.0191 mol Zn × (2 mol HCl/1 mol Zn) = 0.0382 mol HCl
Convert this amount to grams:
0.0382 mol HCl × (36.458 g HCl/1 mol HCl) = 1.39 g HCl
molarity of the CuSO₄ solution = 0.68 moles/L
Explanation:
The formula for molar concentration is:
molar concentration (molarity) = number of moles / solution volume (L)
number of moles = mass / molecular weight
number of moles of CuSO₄ = 12.304 / 159.6
number of moles of CuSO₄ = 0.07709 moles
molar concentration of the CuSO₄ solution = 0.07709 / 0.1127
molar concentration of the CuSO₄ solution = 0.68 moles/L
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Answer:
2 electrons
8 electrons
8 electrons
1 electron (just count in the rings for these ones)
19 protons (it says "P=19" in the middle. The P stands for Protons)
K (it's from Latin medieval Latin "kalium")
39 (add proton and neutron amounts to get the approximate atomic mass--electrons are negligible)
Explanation:
