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Kisachek [45]
3 years ago
10

Find the reagent to sythesize 1- phenyl-1-propanol

Chemistry
1 answer:
vova2212 [387]3 years ago
4 0

Answer:

aqueous acid is used as a reagent.  

Explanation:

Addition of Grignard reagent in aldehyde and followed by the acidification give rise to the primary or secondary alcohol. when the formaldehyde is used than the primary alcohol is formed otherwise secondary alcohol is formed.

in this reaction we also use the aqueous acid for the acidification as a reagent. We add aqueous acid when ethanol is present. This is because ethanol is get converted in the presence of aqueous acid into the chloroethane.  

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¿A qué se debe la coloración de la llama cuando hay un halógeno presente?
Nimfa-mama [501]

Answer:

Green

Explanation:

Positive: A strong green color in the flame indicates the presence of halogens (chloride, bromide, iodide but not fluoride).

8 0
2 years ago
Find the pHpH of a solution prepared from 1.0 LL of a 0.15 MM solution of Ba(OH)2Ba(OH)2 and excess Zn(OH)2(s)Zn(OH)2(s). The Ks
charle [14.2K]

Answer:

pH  = 13.09

Explanation:

Zn(OH)2 --> Zn+2 + 2OH-   Ksp = 3X10^-15

Zn+2 + 4OH-   --> Zn(OH)4-2   Kf = 2X10^15

K = Ksp X Kf

  = 3*2*10^-15 * 10^15

  = 6

Concentration of OH⁻ = 2[Ba(OH)₂] = 2 * 0.15 = 3 M

                Zn(OH)₂ + 2OH⁻(aq)  --> Zn(OH)₄²⁻(aq)

Initial:           0             0.3                      0

Change:                      -2x                     +x

Equilibrium:               0.3 - 2x                 x

K = Zn(OH)₄²⁻/[OH⁻]²

6 = x/(0.3 - 2x)²  

6 = x/(0.3 -2x)(0.3 -2x)

6(0.09 -1.2x + 4x²) = x

0.54 - 7.2x + 24x² = x

24x² - 8.2x + 0.54 = 0

Upon solving as quadratic equation, we obtain;

x = 0.089

Therefore,

Concentration of (OH⁻) = 0.3 - 2x

                                    = 0.3 -(2*0.089)

                                  = 0.122

pOH = -log[OH⁻]

         = -log 0.122

          = 0.91

pH = 14-0.91

     = 13.09

4 0
3 years ago
Does a large ball of aluminum foil have the same properties as a small ball?
dsp73

Answer:

yes

Explanation:

same properties different size

can i have brainliest pls

5 0
3 years ago
3690 J of heat are added to a 21.5 g sample
Fiesta28 [93]

Answer:

693K

Explanation:

The enthalpy change in the iron is 3690J

We now apply the formula for enthalpy change which is ΔH=mC∅ where ∅ is the temperature change, m the mass of the substance, and C the specific heat capacity for the substance.

ΔH in this case is 3690J.

Therefore 3690J=21.5g×0.449J/g.K×∅

as we are looking for ∅, we make it the subject of the formula.

∅=3690J/(21.5g×0.44J/g)

∅=390

Temperature=30°C +390

=420°+273

=693K

6 0
3 years ago
What is the wavelength of these waves?
Pepsi [2]
It measure the distance between two consecutive waves within the phase.
3 0
3 years ago
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