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weqwewe [10]
3 years ago
11

What assumption did you make about the reaction of kmno4 solution and h2c2o4 solution in those determinations that allowed you t

o consider k to be a constant?

Chemistry
1 answer:
a_sh-v [17]3 years ago
8 0
Check the attachment out.. I think thats what you looking for. I hope it helped. :)

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The trapping of heat by carbon dioxide and water vapor is known as the_
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It's known as the greenhouse effect.
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3 years ago
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Ocean tides observed at coastal locations each day are primarily caused by what?
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Ocean tides are caused by mostly wind but can also be caused by earthquakes
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3 years ago
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Calculate the theoretical yield for the bromination of both stilbenes
podryga [215]

Answer:

cinnamic acid - 150 mg

cis-stilbene - 100 μL

trans- stilbene - 100 mg

pyridinium tribromide - 200-385 mg

For this data:

moles of cinnamic acid = 0.150 g/148.16 g/mol = 0.001 mols

Theoretical mass of dibromoproduct formed = 0.001 mol x 307.97 g/mol = 0.312 g

cis-stilbene (100 ul = 0.1 ml)

moles of cis-stilbene = 0.1 ml x 1.01 g/mol/180.25 g/mol = 0.00056 mols

Theoretical mass of dibromoproduct formed = 0.00056 mol x 340.05 g/mol = 0.19 g

trans-stilbene

moles of tran-stilbene = 0.1 g/180.25 g/mol = 0.00055 mols

Theoretical mass of dibromoproduct formed = 0.00055 mol x 340.05 g/mol = 0.19 g

Explanation:

4 0
2 years ago
Metallic copper is formed when aluminum reacts with copper(ii) sulfate. how many grams of metallic copper can be obtained when 5
exis [7]
Answer is: 127 grams <span>rams of metallic copper can be obtained.
</span>Balanced chemical reaction: 2Al + 3CuSO₄ → Al₂(SO₄)₃ + 3Cu.
m(Al) = 54.0 g.
n(Al) = m(Al) ÷ M(Al).
n(Al) = 54 g ÷ 27 g/mol.
n(Al) = 2 mol.
m(CuSO₄) = 319 g.
n(CuSO₄) = 319 g ÷ 159.6 g/mol.
n(CuSO₄) = 2 mol; limiting reactant.
From chemical reaction: n(CuSO₄) : n(Cu) = 3 : 3 (1 : 1).
n(Cu) = 2 mol.
n(Cu) = 2 mol · 63.55 g/mol.
n(Cu) = 127.1 g.
8 0
3 years ago
Lorelai discovers a compound that is 64.8 g C, 13.62 g H, and 21.58 g O. What is the empirical formula of Lorelai's compound
jenyasd209 [6]

The empirical formula of Lorelai's compound is C₄H₁₀O

<h3>Data obtained from the question</h3>
  • C = 64.8 g
  • H = 13.62 g
  • O = 21.58 g
  • Empirical formula =?

<h3>How to determine the empirical formula</h3>

Divide by their molar mass

C = 64.8 / 12 = 5.4

H = 13.62 / 1 = 13.62

O = 21.58 / 16 = 1.35

Divide by the smallest

C = 5.4 / 1.35 = 4

H = 13.62 / 1.35 = 10

O = 1.35 / 1.35 = 1

Thus, the empirical formula of the compound is C₄H₁₀O

Learn more about empirical formula:

brainly.com/question/24297883

#SPJ1

7 0
2 years ago
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