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weqwewe [10]
3 years ago
11

What assumption did you make about the reaction of kmno4 solution and h2c2o4 solution in those determinations that allowed you t

o consider k to be a constant?

Chemistry
1 answer:
a_sh-v [17]3 years ago
8 0
Check the attachment out.. I think thats what you looking for. I hope it helped. :)

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What is the force that opposes motion called?
34kurt

Answer:

Friction

Explanation:

Friction is the name of the force that opposes motion.

8 0
3 years ago
If he(g) has an average kinetic energy of 8750 j/mol under certain conditions, what is the root mean square speed of cl2(g) mole
saw5 [17]
<span>The root mean square speed is given by V_rms = âšRT/M where r, t, and m are the rate constant, temperature and molar mass the gas Average molar kinetic energy of the gas E = 1/2 M * (V_rms)^2 = 8750 ms/1 So (V_rms)^2 = (2 * 8750) / M Molar mass of 2 chlorine atoms in kg is 2 * 35 * 10^(-3) Hence we have (V_rms)^2 = (2 * 8750)/ (2 * 35 * 10^(-3)) (V_rms)^2 = 8750/0.035 = 250000 So V_rms = âš 250000 = 500</span>
5 0
3 years ago
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How is a compound different from a mixture?
Marrrta [24]

Answer: a compound is a chemically made or chemically bonded where as a mixture is just something added like a smoothie

6 0
3 years ago
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Which is the best conductor of electricity (0.1M solution)? Why?
Semmy [17]

Answer:

sulphuric acid as it is strong electrolyte and thus, ionises completely.

Explanation:

3 0
3 years ago
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S-2-iodooctane lost his opticaly activity in soln on tratment wwithNaI. Explain
IceJOKER [234]

Answer:

Repeated SN2 reactions occur leading to the formation of a racemic mixture

Explanation:

S-2-iodooctane is a chiral alkyl halide with an asymmetric carbon atom. The presence of an asymmetric carbon atom implies that it can rotate plane polarized light and thus lead to optical isomerism. The two configurations of the compound are R/S according to the Cahn-Prelong-Ingold system.

However, when S-2-iodooctane is treated with sodium iodide in acetone, repeated SN2 reactions occur since the iodide ion is both a good nucleophile and a good leaving group. Hence a racemic modification is formed in the system with time hence we end up with (±)- Iodooctane.

5 0
3 years ago
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