Answer:
Ba(OH)2 + 2 HCl → BaCl2 + 2 H2O
The reactants are present in equimolar amounts, so there is no excess or limiting reactants.
(0.0500 L) x (0.600 mol/L HCl) x (2 mol H2O / 2 mol HCl) = 0.0300 mol H2O
(4.184 J/g·°C) x (50.0 g + 50.0 g) x (25.82 - 21.73)°C = 1711.256 J
(1711.256 J) / (0.0300 mol H2O) = 57042 J/mol = 57.0 kJ/mol H2O
Explanation:
<span>PPCl5 = ?? atm hop it helps</span>
Number of grams in 1 mole = 6.23 * 10^23
Now, in 15, it would be: 15 / 6.23 * 10^23 = 2.5 * 10^-24 moles (approx.)
In short, Your Answer would be Option C
Hope this helps!
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