There are two classes of membrane transport proteins—carriers<span> and </span>channels<span>. Both form continuous </span>protein<span> pathways across the lipid bilayer. Whereas transport by </span>carriers<span> can be either active or passive, solute flow through </span>channel proteins<span> is always passive.</span>
Answer:
option 3
Explanation:
In non-homologous end joining, the break ends are directly ligated together without the need for a homologous template unlike the homologous repair. this form of repair uses short homologous sequences of DNA termed microhomologies to direct repair and these microhomologies are seen as single-stranded overhangs found on the ends of double-strand breaks. When the overhangs are perfectly compatible, NHEJ ligates and repair the break. When these overhangs are not compatible, imprecise repair leading to deletion of nucleotides can also occur which is much more common .
Answer:
a. Bands at 1kb, 6kb and 8kb
Explanation:
The EcoRI and BamHI are the restriction enzymes which cut the DNA sequence especially a plasmid at specific sites called the restriction sites.
The restriction enzymes produces bands of specific length therefore these restriction enzymes are used to estimate the approximate length of the DNA.
In the given question, the
1. EcoRI- produces two strands of 7 kb and 8 kb
2. BamHI- produces two strands of 1kb and 14kb
This shows that the length of DNA sequence is 15kb
But when the DNA strand are digested with both the enzymes simultaneously then it will produce three bands as:
i) 14 kb can be broken down in 2 bands of 6 kb and 8 kb
ii) 1 kb band is already produced by the Bam HI.
This shows that 1+6+8= 15 kb
Thus, Option-A is correct.
Answer:
At sea level, air pressure is greatest because it is caused by the weight of the entire column of atmosphere at that altitude over that location. As altitude increases, the column of atmosphere gets shorter, and so less weight is pressing down at a given altitude, so atmospheric pressure is reduced.