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3 years ago

Question 37 (1 point)

Mathematics

2 answers:

o-na [289]3 years ago

5 0

Answer:

The probability is:

$P =\frac{1}{16}$

Step-by-step explanation:

Keep in mind that the probability of getting a head is always the same for each

$p = 0.5$

Therefore the probability of not having a head is:

$q = 1-p = 0.5\\q = 0.5$

So if we throw the coin 4 times the probability P of not getting any head is:

$P = q * q * q * q\\\\P = q ^ 4\\\\P = 0.5 ^ 4\\\\$

$P =\frac{1}{16}$

Natalka [10]3 years ago

5 0

0.5=P I believe is the answer

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-4/9x=16/27 alguien que me ayude

Andre45 [30]

<h3>Answer</h3>

First multiply everything by 27

$- \frac{4}{9} x = \frac{16}{27} = \\ 27 \times ( - \frac{4 }{9}x) = 27 \times \frac{16}{27}$

Then approximate the terms with 27 if it's possible (27 and 9) (27 and 27)

$3 \times ( - \frac{4}{1} ) = 16$

So now multiply again

$3 \times ( - 4) = - 12$

And you have

$- 12x = 16$

$x = - \frac{16}{12} = - \frac{4}{3}$

You're welcome if it's right

4 0

4 years ago

CAN SOMEONE PLEASE ANSWER THIS SOON! THANK YOU!

lyudmila [28]

We want to find one-half of the reciprocal of 7/sqrt(98). Let's write down an expression for this:

$\dfrac{1}{2} \times \dfrac{\sqrt{98}}{7}$

We can rewrite 98 into $2 \times 49$

$\dfrac{1}{2} \times \dfrac{\sqrt{2 \times 49}}{7}$

$=\dfrac{1}{2} \times \dfrac{\sqrt{2} \times \sqrt{49}}{7}$

The square root of 49 is 7

$=\dfrac{1}{2} \times \dfrac{\sqrt{2} \times 7}{7}$

$=\dfrac{1}{2} \times\sqrt{2}$

$=\dfrac{\sqrt{2}}{2}$

This should be your answer. Let me know if you need any clarifications, thanks!

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Vesnalui [34]

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8 0

3 years ago

Find the range of the function for the domain {−3, 1, 4.5}.

Nitella [24]

Answer:

D. {4, 0, -3.5}

Step-by-step explanation:

domain (x) = {-3, 1, 4.5}

y= -x + 1

substituting domain/x-values into y= -x + 1

x= -3

y = -(-3) + 1

= 3+1

= 4

x= 1

y = -(1) + 1

= 0

x = 4.5

y = - (4.5) + 1

= -3.5

therefore, range ={4, 0, -3.5}

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Svet_ta [14]

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4 years ago

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