Lol
trouble varies directly as distance
lets say t=trouble and d=distance
t=kd
k is constant
given
when t=20, and d=400
find k
20=400k
divide by 400 both sides
1/20=k
t=(1/20)d
given, d=60
find t
t=(1/20)60
t=60/20
t=3
3 troubles
The answer choice which represents the solution to the inequality as given in the task content is; x>-2 or x≤ 1.
<h3>What is the solution of the give complex inequality?</h3>
On this note, it follows that the inequalities can be solved individually as follows;
-4 < 3x +2
-6 < 3x
x > -2
Also, 3x +2 ≤ 5
3x ≤ 3
x ≤ 1.
Ultimately, the correct answer choice is; Choice C; x>-2 or x≤ 1.
Read more on complex inequality;
brainly.com/question/24761100
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Total number of marbles in the bag =20
Number of blue marbles =4
Now we just want two blue marbles out of four.
Probability of taking out first marble which is blue =4/20
Now after we took out one blue marble , number of blue marbles left are 3.
Probability of taking out second marble which is blue =3/20
Total probability = 4/20 *3/20 = 12/400
So probability of taking out two blue marbles is 0.03 or 12/400.
I think it might be 11x-8
I'm really sorry if that's wrong
x^8/x^5=27
x=3 when you flip the equation (rounded number)
