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Lady_Fox [76]
3 years ago
5

C2h3br Lewis structure

Chemistry
1 answer:
MrRa [10]3 years ago
6 0

HELLO THERE, I HOPE MY ANSWER WILL HELP YOU :)

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THE IMAGE BELOW HAS THE STRUCTURE IMAGE

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tia_tia [17]
1 is correct, i’m not sure if that’s the answer your looking for because of the wording, but if it’s a multiple choice answer then that’s it
5 0
3 years ago
Consider the following reaction at equilibrium. 2CO2 (g) 2CO (g) + O2 (g) H° = -514 kJ Le Châtelier's principle predicts that th
tiny-mole [99]

Answer:

C. at low temperature and low pressure.

Explanation:

  • <em>Le Châtelier's principle </em><em>states that when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.</em>

<em />

  • For the reaction:

<em>2CO₂(g) ⇄ 2CO(g) + O₂(g), ΔH = -514 kJ.</em>

<em></em>

<em><u>Effect of pressure:</u></em>

  • When there is an increase in pressure, the equilibrium will shift towards the side with fewer moles of gas of the reaction. And when there is a decrease in pressure, the equilibrium will shift towards the side with more moles of gas of the reaction.
  • The reactants side (left) has 2.0 moles of gases and the products side (right) has 3.0 moles of gases.

<em>So, decreasing the pressure will shift the reaction to the side with higher no. of moles of gas (right side, products), </em><em>so the equilibrium partial pressure of CO (g) can be maximized at low pressure.</em>

<em></em>

<u><em>Effect of temperature:</em></u>

  • The reaction is exothermic because the sign of ΔH is (negative).
  • So, we can write the reaction as:

<em>2CO₂(g) ⇄ 2CO(g) + O₂(g) + heat.</em>

  • Decreasing the temperature will decrease the concentration of the products side, so the reaction will be shifted to the right side to suppress the decrease in the temperature, <em>so the equilibrium partial pressure of CO (g) can be maximized at low temperature.</em>

<em></em>

  • So, the right choice is:

<em>C. at low temperature and low pressure.</em>

<em></em>

7 0
3 years ago
Determine number of atoms for each element?
Lerok [7]
1 and 1 is the answer
5 0
3 years ago
Porque es importante hablar ayuda <br><br><br><br>xfa​
Sav [38]

Answer:

para poder comunicarse con las personas la vdd no se xd

7 0
2 years ago
A student determines the molar mass of acetone
love history [14]
The Formula of Acetone is C_3H_6O
To find the Mass Molar of a compound, you add the Atomic weights of it's atoms.
If you check the Periodic table:
Atomic Weight of Carbone C: 12.0107
Atomic Weight of Hydrogen: 1.00794
Atomic Weight of Oxygen: 15.9994 

So, you got:
Total Atomic Weight of Carbone in Acetone: 12.0107 * 3 = 36.0321 
Total Atomic Weight of Hydrogen in Acetone: 1.00794 * 6 = 6.04764
Total Atomic Weight of Oxygen in Acetone = 15.9994 * 1 = 15.9994

Now, you add this numbers
36.0321 + 6.04764 + 15.9994 = 58.07914

So, the Molar Mass of Acetone is 58.09714 g/mol

Hope this Helps :D
7 0
3 years ago
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