Answer:
Specific heat of metal of the metal is 0.8394J/g°C
Explanation:
The heat the water gain is the same losing for the metal. The equation is:
m(Metal)*ΔT(Metal)*S(Metal) = m(Water)*ΔT(Water)*S(Water)
<em>Where m is mass: 66.0g water and 28.5g Metal</em>
<em>ΔT is change in temperature: (95.25°C-27.84°C) = 67.41°C for the metal and (27.84°C - 22.00°C) = 5.84°C for the water</em>
<em>And S is specific heat of water (4.184J/g°C) and the metal</em>
<em />
Replacing:
28.5g*67.41°C*S(Metal) = 66.0g*5.84°C*4.184J/g°C
S(Metal) = 0.8394J/g°C
<h3>Specific heat of metal of the metal is 0.8394J/g°C</h3>
<em />
Answer:
There are 0.09996826 moles per liter of the solution.
Explanation:
Molar mass of HNO3: 63.02
Convert grams to moles
0.63 grams/ 63.02= 0.009996826
Convert mL to L and place under moles (mol/L)
100mL=0.1 L
0.009996826/0.1= 0.09996826 mol/L
Answer: Na
The element that is on the left side of the periodic table on the first column, it can lose one in order to become a noble gas.
Answer:
The answer should be fulcrum
Explanation:
It would be easier if you game me choices to pick from
Answer:
0.2298kg of Al
Explanation:
From the equation of reaction
3 moles of Al (81g) is required to mix with 3 moles of NH4ClO4 (352.5g)
Mass of Al required in the fuel mixture for every kilogram (1000g) of NH4ClO4 = 1000×81/352.5 = 229.8g = 229.8/1000 = 0.2298kg