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3 years ago

What is a cosmic microwave background

Physics

1 answer:

Snezhnost [94]3 years ago

6 0

Answer:

The cosmic microwave background, in explosion cosmology, is radiation as a remnant from associate degree early stage of the universe, additionally called "relic radiation". The CBR is faint cosmic background signal filling all area

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Waves combine to produce a smaller or zero-amplitude wave in a process called

vampirchik [111]

ANSWER: Destructive Interference

-This is the exact definition of the question you have provided, look this term up if you do not believe lol.

Hope this Helps!

6 0

3 years ago

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bromine, chlorine, and fluorine are examples of A. halogens B. Metalloids C. Noble Gases or D. Alkali metals

Bumek [7]

A) halogens.

bromine, chlorine and fluorine are found in group 7 of the periodic table. thus they are halogens

4 0

3 years ago

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Which of these best describes how the kinetic energy of carbon dioxide molecules change as the carbon dioxide is heated?

spin [16.1K]

B.
carbon dioxide molecules have more energy; therefore, the kinetic energy increases

4 0

4 years ago

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A radar station detects an airplane approaching directly from the east. At first observation, the range to the plane is 375.0 m

Gekata [30.6K]

Answer:

819.78 m

Explanation:

<u>Given:</u>

OA = range of initial position of the airplane from the point of observation = 375 m
OB = range of the final position of the airplane from the point of observation = 797 m
$\theta$ = angle of the initial position vector from the observation point = $43^\circ$
$\alpha$ = angle of the final position vector from the observation point = $123^\circ$
$\vec{AB}$ = displacement vector from initial position to the final position

A diagram has been attached with the solution in order to clearly show the position of the plane.

$\vec{OA} = OA\cos \theta \hat{i}+OA \sin \theta \hat{j}\\\Rightarrow \vec{OA} = 375\ m\cos 43^\circ \hat{i}+375\ m\sin 43^\circ \hat{j}\\\Rightarrow \vec{OA} = (274.26\ \hat{i}+255.75\ \hat{j})\ m\\\vec{OB} = OB\cos \alpha \hat{i}+OB \sin \alpha \hat{j}\\\Rightarrow \vec{OB} = 797\ m\cos 123^\circ \hat{i}+797\ m\sin 123^\circ \hat{j}\\\Rightarrow \vec{OB} = (-434.08\ \hat{i}+668.42\ \hat{j})\ m$

Displacement vector of the airplane will be the shortest line joining the initial position of the airplane to the final position of the airplane which is given by:

$\vec{AB}=\vec{OB}-\vec{OA}\\\Rightarrow \vec{AB} = (-434.08\ \hat{i}+668.42\ \hat{j})\ m-(274.26\ \hat{i}+255.75\ \hat{j})\ m\\\Rightarrow \vec{AB} = (-708.34\ \hat{i}+412.67\ \hat{j})\ m$

The magnitude of the displacement vector = $\sqrt{(-708.34)^2+(412.67)^2}\ m = 819.78\ m$

Hence, the magnitude of the displacement of the plane is 819.67 m during the period of observation.

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3 years ago

Which circuit has three non-identical resistors that must have the same voltage drop?

Lelu [443]

D do.

All 3 resistors are connected directly across the battery.

5 0

3 years ago