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Mars2501 [29]
2 years ago
5

The difference between the observed points and the regression line points is equal to the:________

Physics
1 answer:
pshichka [43]2 years ago
8 0

The difference between the observed points and the regression line points is equal to the correlation.

The strength and direction of a relationship between two or more variables are described by the statistical measure of correlation, which is given as a number. However, a correlation between two variables does not necessarily imply that a change in one variable is the reason for a change in the values of the other.

Regression expresses the relationship as an equation, whereas correlation assesses the strength of the linear link between two variables. The square of the correlation coefficient, also known as Pearson's r, between the observed and predicted values in a regression is sometimes referred to as R2.

Learn more about correlation here;

brainly.com/question/6563788

#SPJ4

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How much does a 60 kg table weigh
soldier1979 [14.2K]

Answer:

588 N

Explanation:

weigh = Mg

I hope you got that. Thanks and upovote that

5 0
3 years ago
Excellent human jumpers can leap straight up to a height of
Firlakuza [10]

For a human jumper to reach a height of 110 cm, the person will need to leave the ground at a speed of 4.65 m/s.  

We can calculate the initial speed to reach 110 cm of height with the following equation:

v_{f}^{2} = v_{i}^{2} - 2gh

Where:

v_{f}: is the final speed = 0 (at the maximum height of 110 cm)

v_{i}: is the initial speed =?

g: is the acceleration due to gravity = 9.81 m/s²

h: is the height = 110 cm = 1.10 m

Hence, the <u>initial velocity</u> is:

v_{i} = \sqrt{v_{f}^{2} + 2gh} = \sqrt{2*9.81 m/s^{2}*1.10 m} = 4.65 m/s

Therefore, the initial speed that the person must have to reach 110 cm is 4.65 m/s.

You can see another example here: brainly.com/question/13359681?referrer=searchResults

I hope it helps you!

4 0
3 years ago
An elephant kicks a 2.5 kg rock that is initially at rest. The
erma4kov [3.2K]

0.20Answer:

Explanation:

6 0
3 years ago
A net force of 0.7 N is applied on a body. What happens to the acceleration of the body in a second trial if half of the net for
Dmitriy789 [7]

Answer:

The answer  is The acceleration is double its original value.

Explanation:

<h2><u>It is because of the second trial of accelaration. Because of this, an object's acceleration doubles from its original value.</u></h2><h2><u></u></h2>

Hope this helps....

Have a nice day!!!!

6 0
3 years ago
Read 2 more answers
A 91-kg astronaut and a 1300-kg satellite are at rest relative to the space shuttle. The astronaut pushes on the satellite, givi
WARRIOR [948]

Answer:

18.2145 meters

Explanation:

Using the conservation of momentum, we have that:

m1v1 + m2v2 = m1'v1' + m2'v2'

m1 = m1' is the mass of the astronaut, m2=m2' is the mass of the satellite, v1 and v2 are the inicial speed of the astronaut and the satellite (v1 = v2 = 0), and v1' and v2' are the final speed of the astronaut and the satellite. Then we have that:

0 + 0 = 91*v1' + 1300*0.17

v1' = -1300*0.17/91 = -2.4286\ m/s

The negative sign of this speed just indicates the direction the astronaut goes, which is the opposite direction of the satellite.

If the astronaut takes 7.5 seconds to come into contact with the shuttle, their initial distance is:

distance = 2.4286 * 7.5 = 18.2145\ meters

8 0
4 years ago
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