Answer:
588 N
Explanation:
weigh = Mg
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For a human jumper to reach a height of 110 cm, the person will need to leave the ground at a speed of 4.65 m/s.
We can calculate the initial speed to reach 110 cm of height with the following equation:

Where:
: is the final speed = 0 (at the maximum height of 110 cm)
: is the initial speed =?
g: is the acceleration due to gravity = 9.81 m/s²
h: is the height = 110 cm = 1.10 m
Hence, the <u>initial velocity</u> is:

Therefore, the initial speed that the person must have to reach 110 cm is 4.65 m/s.
You can see another example here: brainly.com/question/13359681?referrer=searchResults
I hope it helps you!
Answer:
The answer is The acceleration is double its original value.
Explanation:
<h2><u>
It is because of the second trial of accelaration. Because of this, an object's acceleration doubles from its original value.</u></h2><h2><u>
</u></h2>
Hope this helps....
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Answer:
18.2145 meters
Explanation:
Using the conservation of momentum, we have that:

m1 = m1' is the mass of the astronaut, m2=m2' is the mass of the satellite, v1 and v2 are the inicial speed of the astronaut and the satellite (v1 = v2 = 0), and v1' and v2' are the final speed of the astronaut and the satellite. Then we have that:


The negative sign of this speed just indicates the direction the astronaut goes, which is the opposite direction of the satellite.
If the astronaut takes 7.5 seconds to come into contact with the shuttle, their initial distance is:
