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Mars2501 [29]
2 years ago
5

The difference between the observed points and the regression line points is equal to the:________

Physics
1 answer:
pshichka [43]2 years ago
8 0

The difference between the observed points and the regression line points is equal to the correlation.

The strength and direction of a relationship between two or more variables are described by the statistical measure of correlation, which is given as a number. However, a correlation between two variables does not necessarily imply that a change in one variable is the reason for a change in the values of the other.

Regression expresses the relationship as an equation, whereas correlation assesses the strength of the linear link between two variables. The square of the correlation coefficient, also known as Pearson's r, between the observed and predicted values in a regression is sometimes referred to as R2.

Learn more about correlation here;

brainly.com/question/6563788

#SPJ4

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Answer:

gas

Explanation:

because It is fast and easy

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3 years ago
What type of general wave requires a medium for the wave to travel through
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Mechanical

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7 0
2 years ago
What happens to a radioactive isotope as it decays?
kupik [55]
It becomes a different element
8 0
3 years ago
You drop a rock down a well that is 5.4 m deep. How long does it take the rock to hit the bottom of the well?
Natali5045456 [20]
Equation of motion:

y_{f}=y_{o}+v_{o}t+ \frac{1}{2} at^{2}

Since initial velocity is zero, the second term goes away:

y_{f}=y_{o}+0+ \frac{1}{2} at^{2}

y_{f}=y_{o}+\frac{1}{2} at^{2}

y_{f}-y_{o}= \frac{1}{2} at^{2}

y_{f}-y_{o}=5.4m

5.4m= \frac{1}{2} at^{2}

\frac{2(5.4m) }{a} = t^{2}

a = g = 9.81  \frac{m}{ s^{2}}

\frac{2(5.4m) }{9.81 \frac{m}{ s^{2} } } = t^{2}

1.1 s^{2} = t^{2}\sqrt{1.1 s^{2}} =  \sqrt{t^{2}}

<u><em>t = 1.05s</em></u>
4 0
3 years ago
Read 2 more answers
A car weighs 15,000 N, and its tires are inflated to a pressure of 190 kPa.How large is the area of the car's tires that are in
Elan Coil [88]
Pressure is the force applied perpendicular to a surface divided by the area of the surface. Therefore, from the given values, we can easily calculate the area by dividing the force to the pressure. We do as follows:

Area = F / P
Area = 15000 / 190000
Area = 0.0789 m^2

Hope this answers the question. Have a nice day.
7 0
3 years ago
Read 2 more answers
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