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hoa [83]
3 years ago
9

Do steps 3 as outlined in the lab guide. Record your results in the appropriate blanks

Chemistry
2 answers:
spin [16.1K]3 years ago
8 0

A= 56

B= 27

c= 12

D= 8

E= 3

F= 3

G= 1

H= 1

is what the edg. example shows but any answers are accepted!!

Fittoniya [83]3 years ago
6 0

Answer:

A=  27

B=  16

C=  9

D=  4

E=  2

F=  2

G=  0

H= 0

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elena55 [62]

Answer:

its B its B its B its B

Explanation:

3 0
3 years ago
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Mothballs are composed primarily of the hydrocarbon naphthalene (C10H8). When 1.025 g of naphthalene is burned in a bomb calorim
Serggg [28]

Answer:

\Delta E_{rxn} for combustion of naphthalene is -5164 kJ/mol

Explanation:

\Delta E_{rxn}=C_{calorimeter}\times \Delta T_{calorimeter}

where, C refers heat capacity and \Delta T refers change in temperature.

Here, \Delta T_{calorimeter}=(32.33-24.25)^{0}\textrm{C}=8.08^{0}\textrm{C}

So, \Delta E_{rxn}=(5.11\frac{kJ}{^{0}\textrm{C}})\times (8.08^{0}\textrm{C})=41.3kJ

\Delta E_{rxn} is generally expressed in terms of per mole unit of reactant. Also, \Delta E_{rxn} should be negative as it is an exothermic reaction (temperature increases).

Molar mass of naphthalene is 128.17 g/mol

So, 1.025 g of naphthalene = \frac{1.025}{128.17}moles of naphthalene

                                              = 0.007997 moles of naphthalene

\Delta E_{rxn}=-\frac{41.3kJ}{0.007997mol}=-5164kJ/mol

5 0
3 years ago
Sven perform this reaction with 15.0 grams of sodium sulfate and an excess of iron (III) phosphate to make iron (III) sulfate an
VARVARA [1.3K]

Answer:

85.5%

Explanation:

To get the experimental value, you need to convert 15.0 grams of Na2SO4 to grams of Na3PO4. You do this with stoichiometry.

Convert grams of Na2SO4 to moles with molar mass. Then convert to moles of Na3PO4 with the mole-to-mole ratio according to the balanced chemical equation. Then convert moles of Na3PO4 to grams with the molar mass.

15.0 g Na2SO4 x (1 mol/142.04 g) x (2 Na3PO4/3Na2SO4) x (163.94 g/1 mol) = 11.7 g Na3PO4

Percent Yield = (actual value/experimental value) x 100

Actual Value = 10.0 g

Experimental Value = 11.7 g

10.0g/11.7 g = 85.5%

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3 years ago
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Brut [27]

Answer:

C

Explanation:

A is higher up therefore giving it higher potential energy, height goes hand ik hand with potential energy

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denpristay [2]
A. An octopus

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