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Liono4ka [1.6K]
3 years ago
14

Factor the trinomial x^2 - 16x +63

Mathematics
1 answer:
Butoxors [25]3 years ago
3 0
Factor the following:
x^2 - 16 x + 63
The factors of 63 that sum to -16 are -7 and -9. So, x^2 - 16 x + 63 = (x - 7) (x - 9):
Answer:  (x - 7) (x - 9)
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Use the Babylonian method to estimate the square root of 107 to the nearest tenth. 10.2 10.3 10.5 10.4
Delicious77 [7]
I think the answer is B 10.3. Hopefully this helped!! ( and hope I got it correct ) =“)
7 0
3 years ago
The slope of a line is -1/4 and the y-intercept is 8. Whats the x-intercept?
Fed [463]
Slope = -1/4
y-interept = 8
⇒equation:  y = -1/4x + 8

x-intercept ⇒ when y = 0
0 = -1/4x + 8
1/4x = 8
x = 8 x 4 
x = 32

Answer: x-intercept = (32,0)
7 0
3 years ago
Can somebody help me? I’m already failing :(
Yuliya22 [10]

Answer:

125

Step-by-step explanation:

f(1)= the first time (32,000)

n= 9

r= .5 (each term is being mulitplied by .5 to get the next one

We have

32,000*(.5)^(9-1)

32,000*(.5)^8

=125

5 0
3 years ago
I'm stuck on this one:( help me please ​
ZanzabumX [31]

Answer:

Step-by-step explanation:

f-1(x) is the inverse of f(x)

to find the inverse let’s set the equation up like this

y = 4x -2

now we’ll switch x and y

x = 4y -2

and solve for y

x + 2 = 4y

x/4 + 2/4 = y

the inverse is

y = x/4 + 1/2

this equation is written in y = mx + b form

where b = y intercept

so the y intercept is 1/2

6 0
3 years ago
Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at
kari74 [83]

Answer: 5 km walking and 30 km by bus

Step-by-step explanation:

Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at an average speed of 60 km / h until he got to school. The total distance from his home to school is 35 km, and the entire trip took 1.5 hours. How many km did Yochanan cover by walking and how many did he cover by travelling on the bus?

walking - 5km/h                                         bus - 60km/h

distance walking - d₁                                 distance bus - d₂

time walking - t₁                                         time bus - t₂

d₁ + d₂ = 35

t₁ + t₂ = 1.5

v = d/t

vwalking = d₁/t₁

5 = d₁/t₁ ⇒ d₁ = 5t₁

vbus = d₂/t₂

60 = d₂/t₂ ⇒ d₂ = 60t₂

d₁ + d₂ = 35 ⇒ 5t₁ + 60t₂ = 35

_________________________

5t₁ + 60t₂ = 35

t₁ + t₂ = 1.5  (*-5)

5t₁ + 60t₂ = 35

-5t₁ -5t₂ = -7.5   (+)

__________________________

55t₂ = 27.5

t₂ = 27.5/55 = 0.5 h

t₁ + t₂ = 1.5 ⇒ t₁ = 1.5 - 0.5 = 1h

d₁ = 5t₁ ⇒ d₁ = 5.1 = 5 km

d₂ = 60t₂ ⇒ d₂ = 30.0.5 = 30 km

6 0
3 years ago
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