58 because it couldn’t be 45 and 67 so it’s either 78 or 58 but since i need some points i’m acting like i know the answer
Using the Factor Theorem, it is found that yes, it is possible for a sixth degree polynomial function with integer coefficients to have no real zeroes, as they can have three complex-conjugate pairs.
<h3>What is the Factor Theorem?</h3>
The Factor Theorem states that a polynomial function with roots is given by:
In which a is the leading coefficient.
If a complex number is a root of a function, it's conjugate will also be a root. Thus, with three pairs of complex-conjugate roots, for example, , a sixth degree function with no real zeros is formed, so the answer is Yes.
More can be learned about the Factor Theorem at brainly.com/question/24380382
U would replace ur -4 with the x’s so ur problem would look like <-2(-4)-10> and then solve that and u would get (2) for ur answer...
25 × x = 45
or 25÷100 × x= 45
multiplying both sides by 100 and dividing both sides by 25, we have x = 45×100÷25
therefore, x = 180
( if you use a calculator simply enter 45×100÷ 25)