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4 years ago

8

What is forty - one thousand two hundred forty - three in standard form

2 answers:

wlad13 [49]4 years ago

7 0

41,243 will be the answer

kolbaska11 [484]4 years ago

5 0

41,243 Is the answer.

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Transitive property: if ____=-11^3 and -11i^3=11i then _____=11i

Semenov [28]

Answer:

if -11i^3 =-11^3 and -11i^3=11i then -11^3=11i

if I'm wrong pls correct me but I'm pretty sure this is

5 0

3 years ago

Please Please Please Help Me On These 2 Math Questions!!!!! I GIVE THANKS!!!!

Mars2501 [29]

A. After the mod. One wall is “x” longer than original (horizontal in diagram) and the other is “x” shorter (vertical)
(30+x)(30-x)

b. He original area = 30 x 30 = 900 sq. ft.
The mod. Area is (30+6)(30-6) = 36x24= 764 sq. ft.

So the room was largest to begin with when it was a square

3 0

3 years ago

Plz Help me<br><br>3x + 5y = 13 <br>2x + y = 4

Finger [1]

Answer:

solve simultaneously

start by labeling them equation 1 and 2 then choose whether you want to make x or y the subject from knew of the equations

7 0

3 years ago

Steel Factory Workers Ages

igor_vitrenko [27]

Solution: We are given the population mean $=42$

Now, in order to find which shift's mean is closest to population mean, we will find the mean of each shift.

The mean of shift 1 is:

$Mean=\frac{18+25+56+42+29+38+54+47+35+30}{10}=\frac{374}{10}=37.4$

The mean of shift 2 is:

$Mean=\frac{23+19+50+49+67+34+30+59+40+33
}{10}=\frac{404}{10}=40.4$

The mean of shift 3 is:

$Mean=\frac{19+22+24+40+45+29+33+29+39+59 }{10}=\frac{339}{10}=33.9$

The mean of shift 4 is:

$Mean=\frac{21+23+25+40+35+19+70+40+22+23 }{10}=\frac{318}{10}=31.8$

We clearly see the mean of shift 2 is close to the population mean. Hence the option B) Shift 2 is correct.

7 0

3 years ago

Read 2 more answers

Two distinct number cubes, one red and one blue, are rolled together. Each number cube has sides numbered 1 through 6.

algol [13]

Answer:

7/18

Step-by-step explanation:

First we need to find what values of sum we can have.

The minimum value for a cube is 1, so the minimum value for the sum is 2.

The maximum value for a cube is 6, so the maximum value for the sum is 12.

Now, we find the multiples of 6 and the multiples of 4 between 2 and 12:

4, 6, 8, 12.

To have a sum of 4, we can have the pairs:

(1,3), (2,2), (3,1)

To have a sum of 6, we can have the pairs:

(1,5), (2,4), (3,3), (4,2), (5,1)

To have a sum of 8, we can have the pairs:

(2,6), (3,5), (4,4), (5,3), (6,2)

To have a sum of 12, we can have the pairs:

(6,6)

So we have 14 pairs among the 36 (6 possibilities of each cube, so 6*6=36) total possibilities of pairs, so the probability is P = 14/36 = 7/18

5 0

3 years ago