What is the % by mass of H2O in 10.0 g of Ba(OH)2.8H2O

Sound Wave A is moving through a medium that is decreasing in temperature. Sound Wave B is moving from a liquid to a gas medium.

olganol [36]

Answer: they will slow down

3 0

3 years ago

Read 2 more answers

Please show all work chemistry thanks 2,3 and 4

nikitadnepr [17]

Answer: 2) 0.21 mole H2O

3) 0.50 mole K2O

4) 123 g Ca( NO3)2

Explanation: solution attached.

For number 2 to find the number of moles of H2O just divide the given in molecules with the Avogadro's number.

For 3 convert grams of K2O to moles by using 1 mole of K2O is equal to the molar mass of K2O

For number 4 moles to grams. Same process with number 3

3 0

3 years ago

What is 165 lb in kilograms (kg)? 1 kg = 2.20 lb (please show work) ASAP

Slav-nsk [51]

165 Pounds (lbs) = 74.84 Kilograms (kg)
1 lbs = 0.453592 kg 1 kg = 2.204623 lbs

5 0

3 years ago

Compound has a molar mass of and the following composition: elementmass % carbon47.09% hydrogen6.59% chlorine46.33% Write the mo

snow_lady [41]

The given question is incomplete. The complete question is:

Compound X has a molar mass of 153.05 g/mol and the following composition:

element mass %

carbon 47.09%

hydrogen 6.59%

chlorine 46.33%

Write the molecular formula of X.

Answer: The molecular formula of X is $C_6H_{10}Cl_2$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C= 47.09 g

Mass of H = 6.59 g

Mass of Cl = 46.33 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{47.09g}{12g/mole}=3.92moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.59g}{1g/mole}=6.59moles$

Moles of Cl = $\frac{\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac{46.33g}{35.5g/mole}=1.30moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{3.92}{1.30}=3$

For H = $\frac{6.59}{1.30}=5$

For Cl = $\frac{1.30}{1.30}=1$

The ratio of C : H: Cl= 3: 5 :1

Hence the empirical formula is $C_3H_5Cl$

The empirical weight of $C_3H_5Cl$ = 3(12)+5(1)+1(35.5)= 76.5g.

The molecular weight = 153.05 g/mole

Now we have to calculate the molecular formula.

$n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{153.05}{76.5}=2$

The molecular formula will be= $2\times C_3H_5Cl=C_6H_{10}Cl_2$

7 0

3 years ago

Why scientists use mass instead of weight for their measurements

QveST [7]

An objects weight is how hard gravity is pulling on it. We think the weight is the same everywhere ... because we all live on the surface of the planet Earth! But in orbit it would not push on the scales at all. The scales would show 0 kg ... but themass is still 100 kg !

5 0

3 years ago