Increase the volume of gas particles of H2 and of I2 will decrease the rate of the reaction.
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Answer:
D: 60 grams.
Explanation:
If you look at the x-axis and where it says 50 degrees Celsius, you can see that it takes 20 grams of solute to be saturated at 100 GRAMS of solvent. However, the question is asking for the amount of solute to saturate a 300 GRAM solution.
This means you will have to multiply the amount of solute needed at 100 grams by 3 to get you to the amount needed for 300 grams.
20 times 3 will get you to your answer, 60 grams.
Answer:
Mass of sample in mg = 15,285 mg
Explanation:
Given:
Volume of urine sample = 15 ml
Density of sample = 1.019 g/ml
FInd:
Mass of sample in mg
Computation:
Mass = density x volume
Mass of sample in mg = Volume of urine sample x Density of sample
Mass of sample in mg = 1.019 x 15
Mass of sample in mg = 15.285 gram
Mass of sample in mg = 15.285 x 1,000
Mass of sample in mg = 15,285 mg
Answer:
The answer to your question is: 101.2 g of CO2
Explanation:
C = 27.6 g
O₂ = 86.5 g remained 12.9 g
O₂ that reacted = 86.5 - 12.9 = 73.6 g
C + O₂ ⇒ CO₂ The equation is balanced
27.6 73.6 ?
MW 12 32 44
Rule of three
12 g of C------------------ 44 g CO2
27.6 g C ------------------ x
x = 27.6(44)/12 = 101.2 g of CO2
32 g of O2 --------------- 44 g of CO2
73.6 g of O2 ------------ x
x = 73.6(44)/32 = 101.2 g of CO2
Example:
Mass = ?
Density = 25 g/mL
Volume = 5 mL
therefore:
d = m / V
25 = m / 5
m = 25 x 5
m = 125 g
hope this helps!
