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AlekseyPX
3 years ago
13

Need Help For This Question

Mathematics
2 answers:
Agata [3.3K]3 years ago
8 0

For this case we have to define function transformation that:

Let k> 0:

To graph y = f (x) + k, the graph is displayed k units up.

To graphy = f (x) -k, the graph is displayed k units units down.

Let h> 0:

To graphy = f (x-h), the graph moves units to the right.

To graph y = f (x + h), the graph moves h units to the left.

We have y = - \sqrt [3] {x}

It moves 7 units up and 4 to the right.

So we have to:

h = 4\\k = 7

The shifted graphic is:

y = - \sqrt [3] {x-4} +7

ANswer:

y = - \sqrt [3] {x-4} +7

Neko [114]3 years ago
6 0

Answer:

The Answer is B

Step-by-step explanation:

+7 at the end means up 7

The - 4 in the middle represents right 4

These are found using basic rules of translating equations

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Please show working out thanks
IgorLugansk [536]

Answer:

10m x 15m

Step-by-step explanation:

You are given some information.

1. The area of the garden: A₁ = 150m²

2. The area of the path: A₂ = 186m²

3. The width of the path: 3m

If the garden has width w and length l, the area of the garden is:

(1) A₁ = l * w

The area of the path is given by:

(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36

Multiplying (2) with l gives:

(3) A₂l = 6l² + 6lw + 36l

Replacing l*w in (3) with A₁ from (1):

(4) A₂l = 6l² + 6A₁ + 36l

Combining:

(5) 6l² + (36 - A₂)l +6A₁ = 0

Simplifying:

(6) l² - 25l + 150 = 0

This equation can be factored:

(7) (l - 10)*(l - 15) = 0

Solving for l we get 2 solutions:

l₁ = 10, l₂ = 15

Using (1) to find w:

w₁ = 15, w₂ = 10

The two solutions are equivalent. The garden has dimensions 10m and 15m.

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Step-by-step explanation:

i took it and was correct

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