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stira [4]
3 years ago
9

John, a hotel owner​

Mathematics
2 answers:
Ann [662]3 years ago
8 0

Answer:

A hotel owner .

Step-by-step explanation:

scoundrel [369]3 years ago
4 0

Answer:

Is there more to this question?

Step-by-step explanation:

If thisi was supposed to go under english it is missing a period.

John, a hotel owner.

I hope John is successful!

Hope this helps!

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The answer and explanation to question 1
xxMikexx [17]

Answer:

20, 31, 33, 35, 55, 57, 58, 59, 72, 73, 79, 86, 87, 88

Step-by-step explanation:

The data set is split by digit. So 2|0 becomes 20. 5|5 becomes 55. Using this method, the data set is

20, 31, 33, 35, 55, 57, 58, 59, 72, 73, 79, 86, 87, 88

7 0
3 years ago
1.
stiks02 [169]

Answer:

a. 10, 16

b. 211, 311

c. 10 , 12.5

d. -13, -22

Step-by-step explanation:

In an arithmetic sequence, there is a constant difference, which is the difference between a term and the previous term. We find the constant different for each sequence, and we add it to the second term to find the third term. Then we add the constant difference to the third term to find the fourth term.

a.

4 - (-2) = 6

3rd term: 4 + 6 = 10

4th term: 10 + 6 = 16

b.

111 - 11 = 100

3rd term: 111 + 100 = 211

4th term: 211 + 100 = 311

c.

7.5 - 5 = 2.5

3rd term: 7.5 + 2.5 = 10

4th term: 10 + 2.5 = 12.5

d.

-4 - 5 = -9

3rd term: -4 + (-9) = -13

4th term: -13 + (-9) = -22

4 0
3 years ago
Kayden is a stunt driver. One time, during a gig where she escaped from a building about to explode(!), she drove at a constant
solniwko [45]

Answer:

The answer is D(t) = 160 - 25t

Step-by-step explanation:

well khan academy said it lol

7 0
4 years ago
PLEASE HELP QWQ AsAp with these 4 questions
den301095 [7]

Answer:

Step-by-step explanation:

I can't believe I'm doing this for 5 points, but ok!

For the first 3, we are going to multiply to find the value of that 3 x 3 matrix by picking up the first 2 columns and plopping them down at the end and then multiplying through using the rules for multiplying matrices:

\left[\begin{array}{ccccc}7&4&6&7&4\\-4&8&9&-4&8\\1&8&7&1&8\end{array}\right]  and from there find the sum of the products of the main axes minus the sum of the products of the minor axes, as follows (I'm not going to state the process in the next 2 problems, so make sure you follow it here. This is called the determinate. The determinate is what you get when you evaluate or find the value of a matrix. Just so you know):

(7*8*7)+(4*9*1)+(6*-4*8)-[(1*8*6)+(8*9*7)+(7*-4*4)] which gives us:

392 + 36 - 192 - [48 + 504 - 112] which simplifies to

236 - 440 which is -204

On to the second one:

\left[\begin{array}{ccccc}-8&-4&-1&-8&-4\\1&7&-3&1&7\\8&9&9&8&9\end{array}\right] and multiplying gives us

(-8*7*9)+(-4*-3*8)+(-1*1*9)-[(8*7*-1)+(9*-3*-8)+(9*1*-4)] which gives us:

-504 + 96 - 9 - [-56 + 216 - 36] which simplifies to

-417 - 124 which is -541, choice c.

Now for the third one:

\left[\begin{array}{ccccc}-2&-2&-5&-2&-2\\2&7&-3&2&7\\8&9&9&8&9\end{array}\right] and multiplying gives us

(-2*7*9)+(-2*-3*8)+(-5*2*9)-[(8*7*-5)+(9*-3*-2)+(9*2*-2)] which gives us:

-126+48-90-[-280+54-36] which simplifies to

-168 - (-262) which is 94, choice c again.

Now for the last one. I'll show you the set up for the matrix equation; I solved it using the inverse matrix. So I'll also show you the inverse and how I found it.

\left[\begin{array}{cc}-4&-5&\\-6&-8\\\end{array}\right] \left[\begin{array}{c}x\\y\\\end{array}\right] = \left[\begin{array}{c}-5\\-2\\\end{array}\right] and I found the inverse of the 2 x 2 matrix on the left.

Find the inverse by:

* finding the determinate

* putting the determinate under a 1

* multiply that by the "mixed up matrix (you'll see...)

First things first, the determinate:

|A| = (-4*-8) - (-6*-5) which simplifies to

|A| = 32 - 30 so

|A| = 2; now put that under a 1 and multiply it by the mixed up matrix. The mixed up matrix is shown in the next step:

\frac{1}{2}\left[\begin{array}{cc}-8&5\\6&-4\end{array}\right]  (to get the mixed up matrix, swap the positions of the numbers on the main axis and then change the signs of the numbers on the minor axis). Now we multiply in the 1/2 to get the inverse:

\left[\begin{array}{cc}-4&\frac{5}{2}\\3&-2\\\end{array}\right] Multiply that inverse by both sides of the equation. This inverse "undoes" the matrix that's already there (like dividing the matrix that's already there by itself) which leaves us with just the matrix of x and y. Multiply the inverse matrix by the solution matrix:

\left[\begin{array}{c}x&y\end{array}\right] =\left[\begin{array}{cc}-4&\frac{5}{2} \\3&-2\end{array}\right] *\left[\begin{array}{c}-5&-2\\\end{array}\right] and that right side multiplies out to

x = 20 - 5 which is

x = 15 and

y = -15 + 4 which is

y = -11

(It works, I checked it)

7 0
3 years ago
Solve for t.
wlad13 [49]

One solution was found :  t ≤ -13 (number 4)

Pull out like factors :

-3t - 39  =   -3 • (t + 13)

Divide both sides by  -3  

Remember to flip the inequality sign:  

Solve Basic Inequality :

Subtract  13  from both sides to get t≤−13

7 0
4 years ago
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