Answer:
- see the attachment for a graph
- yes, you can carry 5 math books in one load (along with 0–2 science books)
Step-by-step explanation:
If x and y represent the number of math and science books you're carrying, respectively, then 3x and 4y represent their weights in pounds.
The total weight of the carry will be 3x+4y, and you want that to be at most 24 pounds. The expression modeling this is ...
... 3x +4y ≤ 24
A graph of this inequality is shown in the attachment. (We have added the constraints that the number of books not be negative.)
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5 math books will weigh 5·3 = 15 pounds, so will be within the limit you can carry.
Answer: x =(3-√157)/2=-4.765
x =(3+√157)/2= 7.765
Step-by-step explanation:
Answer:
The probability of picking a black card at random, from a deck with 3 black cards and 7 red ones is 0.3.
Step-by-step explanation:
We will assume that we have 3 black cards and 7 black cards, for a total of 10 cards. Since we are taking one card at random, we can assume that each card is equally likely to be drawn. We have the following event A: The drawn card is a black. We will find the probability of A as counting the number of outcomes that make A to occur and divide it by the total number of possibilities. We are drawing one card, so we have 10 possibilities to be picked. Out of those 10, only 3 cards are black, hence we have 3 possibilites of picking a black card.
Then,
P(A) = 3/10 = 0.3.
Answer:
The area is multiplied by 4
Step-by-step explanation:
4x4=16 (area 1)
4(x2)x4(x2)=64 (area 2 (with the measurements doubled)
64/16=4