Answer: a. 1.981 < μ < 2.18
b. Yes.
Step-by-step explanation:
A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.
First, we calculate mean of the sample:


2.08
Now, we estimate standard deviation:


s = 0.1564
For t-score, we need to determine degree of freedom and
:
df = 12 - 1
df = 11
= 1 - 0.95
α = 0.05
0.025
Then, t-score is
= 2.201
The interval will be
± 
2.08 ± 
2.08 ± 0.099
The 95% two-sided CI on the mean is 1.981 < μ < 2.18.
B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.
Answer:
32
Step-by-step explanation:
32 × 1 = 32
8 × 4 = 32
Therefore, the LCM is 32
Answer:
If its asking you to round to the nearest tenths place then its 0.2
remember that if the number you're using to round is 5 or higher you add 1. If its 4 or lower it stays the same
X intercept: y = 0
y= -3/4x -4
0 = -3/4 x - 4
4= -3/4 x
4 • -4/3 = x
-5.3 = x
y intercept: x = 0
y = -3/4 x -4
y = -3/4 (0) -4
y = -4
the points are (-5.3, 0) and (0, -4)
Let`s say that the expression is written in the form:a * 10^k.4 * 10^3 + 4 * 10^2 = = 4 * 10 * 10^2 + 4 * 10^2 = = 40 * 10^2 + 4 * 10^2 = = 44 * 10^2 = 4.4 * 10^3.Answer:a = 4.4 and k = 3 and the expression in the scientific notation is:4.4 * 10^3.