Linolenic acid (C18H30O2) can be hydrogenated to stearic acid by reacting it with hydrogen gas according to the equation: C18H30
1 answer:
1.998 ml of hydrogen gas volume is is required to react with 10.5 g of linolenic acid in this reaction.
Explanation:
Data given:
mass of linolenic acid is given = 10.5 grams
atomic mass of linoleinic acid = 278.43 grams/mole
volume of hydrogen required at STP = ?
Balance chemical reaction:
C18H30O2 + 3H2 --->C18H36O2
moles of linoleinic acid given =
putting the values in the equation:
moles of linoleinic acid =
= 0.037 moles
from the balanced equation:
1 mole of linoleinic acid reacts with 3 moles of hydrogen
so, 0.037 moles will react with x moles of hydrogen gas
=
x = 0.111 moles of water
volume or mass = atomic mass x number of moles
volume of hydrogen gas= 1.998 ml
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The full question is shown in the image attached
Answer:
See explanation
Explanation:
In naming an alkane, the first thing we do is to obtain the parent chain by counting the number of carbon atoms in the chain.
When we obtain that, then we identify the substituents and number them in such a way that they have the lowest numbers. The compounds shown have the following names according to the order in which the structures appear in the image attached;
1. 2-methyl propane
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3. 2,2,3,3-tetramethyl butane
4. 5-ethyl-2,4-dimethyl octane
Answer:- Formula of the hydrate is and it's name is Iron(III)sulfate pentahydrate.
Solution:- As per the given information, there is 18.4% water in the hydrate. If we assume the mass of the hydrate as 100 grams then there would be 18.4 grams of water and 81.6 grams of Iron(III)sulfate present in the hydrate.
Molar mass for Iron(III)sulfate is 399.88 gram per mol and the molar mass for water is 18.02 gram per mol.
We will calculate the moles of Iron(III)sulfate and water present in the compound on dividing their grams by their molar masses as:
=
=
Now, the next step is to calculate the mol ratio and for this we divide the moles of each by the least one of them means whose moles are less. Here, the moles of Iron(III)sulfate are less than moles of water. So, we divide the moles of each by 0.204.
= 1
= 5
There is 1:5 mol ratio between Iron(III)sulfate and water. So, the formula of the hydrate is and the name of the hydrate is Iron(III)sulfate pentahydrate.