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Sunny_sXe [5.5K]
3 years ago
10

Sulfur has an atomic mass of 32 u and Avogadro's number is 6 × 1023 formula units/mole. The number of sulfur atoms in 1 g of sul

fur is:___________
Chemistry
1 answer:
Vikki [24]3 years ago
6 0

Answer:

The number of sulfur atoms in 1 g of sulfur is:- 1.875\times 10^{22} atoms

Explanation:

Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by N_0.

Avogadro constant:-

N_a=6\times 10^{23}

Given atomic mass of sulfur = 32 u

Which means that:-

32 g of sulfur contains 6\times 10^{23} of atoms

Also,

1 g of sulfur contains \frac {6\times 10^{23}}{32} of atoms

<u>So, The number of sulfur atoms in 1 g of sulfur is:- 1.875\times 10^{22} atoms</u>

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Which reactant will be used up first if 78.1g of o2 is reacted with 62.4g of c4h10?
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Reagent O₂ will be consumed first.

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Then, by reaction stoichiometry, the following amounts of reactants and products participate in the reaction:

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The molar mass of the compounds that participate in the reaction is:

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Then, by reaction stoichiometry, the following mass quantities of reactants and products participate in the reaction:

  • C₄H₁₀: 2 moles* 58 g/mole= 116 g
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  • CO₂: 8 moles* 44 g/mole= 352 g
  • H₂O: 10 moles* 18 g/mole= 180 g

If 78.1 g of O₂ react, it is possible to apply the following rule of three: if by stoichiometry 416 g of O₂ react with 116 g of C₄H₁₀, 62.4 g of C₄H₁₀ with how much mass of O₂ do they react?

mass of O_{2} =\frac{416grams of O_{2}*62.4 grams ofC_{4}H_{10}   }{116 grams of C_{4}H_{10}}

mass of O₂= 223.78 grams

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