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Watch the animation depicting Rutherford's experiment and choose which of the following conclusions are correct.Check all that a

Blababa [14]

Answer:

1. The mass of an atom is concentrated at the nucleus.

3. Positive charge is condensed in one location within the atom.

4. The majority of the space inside the atom is empty space.

6. The atom contains a positively charged nucleus.

Explanation:

When J.J Thmpson discovered the electron, he depicted the atom by the plum pudding model: a solid dough of homogeneously distributed positive charge (the pudding) containing negatively charged electrons (the plums).

Later, the scientist Ernest Rutherford, with its experiment of the gold foil experiment showed that the subatomic particles where not all concentrated in a solid part.

When a thin gold foil was bombarded with alpha particles (positively charged nuclei of helium atoms), most of the particles went through the gold sheet, with little deviation, but some particles bounded with a high deviation.

Such few high deviations were explained by the fact that there was a heavy region in the atom (the core or nucleus) with the positive charge that repelled the positively charged alpha particles.

Thus, the mass of the atom was conentrated at the nucleus (choice 1), where the positive charge is distributed in one location, which is the nucleus (not over the entire atom, just on the nucleus) discarding the choice number 2 (that a positive charge is spread equally over the atom) and proving choices 3 (the positive charge is condensed in one location within the atom) and 6 (the atom contains a positively charged nucleus).

Since most of the particles indeed went through the nucleus, this nucleus has to occupy little space, and most of the atom was empty space, proving choice 4 (the majority of the space inside the atom is empty space).

6 0

4 years ago

_Al + _Fe(NO3)2 -->_Fe + __Al(NO3)3

romanna [79]

4Al+6Fe(NO3)2= 6Fe+4Al(NO3)3

4 0

3 years ago

Silver occurs in trace amounts in some ores of lead, and lead can displace silver from solution: Pb(s) + 2Ag+ (aq) LaTeX: \longr

VikaD [51]

Answer : The value of $\Delta G^o$ and K is, -180 kJ/mol and $3.6\times 10^{31}$