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tamaranim1 [39]
2 years ago
8

A sample of gas occupies a volume of 350.0 mL at 840mm Hg and 33°C. Determine the volume of this sample at 600 mm By and 52°C​

Chemistry
1 answer:
insens350 [35]2 years ago
7 0

Answer:

V₂ = 520.42 mL

Explanation:

Given data:

Initial volume = 350.0 mL

Initial pressure = 840 mmHg

Initial temperature = 33°C (33 +273 = 306 K)

Final temperature = 52°C (52+273 = 325 K)

Final volume = ?

Final pressure = 600 mmHg

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 840 mmHg × 350.0 mL × 325 K / 306 K × 600 mmHg

V₂ = 95550000 mmHg.mL.K /183600 K.mmHg

V₂ = 520.42 mL

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A sample of gas occurs 9.0mL at a pressure of 500mmHg. A new volume of the same sample is at 750mmHg. Use two significant figure
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Explanation:

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Part V Write the (a) half reaction of oxidation, (b) half reaction of reduction, & (c) the balanced redox reaction for all o
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Answer:

Explanation:

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c. Balanced redox reaction

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