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dimulka [17.4K]
3 years ago
15

Enter an equation of the form y= mx for the line that passes through the

Mathematics
1 answer:
hammer [34]3 years ago
5 0

Answer:

y = 13x

Step-by-step explanation:

gradient = 13

x = 0

y = 0

\frac{Δy}{Δx}

so  \frac{y - 0}{x - 0} = 13

cross multiply and you get

y = 13x

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2ab+6a+12abc factored completely
pav-90 [236]
2a(b+3+4bc) 
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3 years ago
oel biked 9 miles east and then 12 miles north. If he biked back to his starting point using the most direct route, how many mil
kvasek [131]

Answer:

36 miles

Step-by-step explanation:

(Imagine a huge triangle on a perfectly open space-- not with streets or houses or cornfields.)

The dimensions of the two sides given are multiples of a classic Pythagorean Triple: 3, 4, 5.    3^{2} + 4^{2} = 5^{2}  

9 is 3x3, 12 is 3x4 so the remaining side would be 3x5  15

Add those 3 sides to get the total distance, 36 miles.

6 0
3 years ago
The sum of three consecutive integers is -15.
zhuklara [117]
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4 0
1 year ago
Read 2 more answers
In your lab, a substance's temperature has been observed to follow the function T(x) = (x + 5)3 + 7. The turning point of the gr
OleMash [197]
So essentially, this is a cubic function where T(x) = y, and:
y =  {(x+5)}^{3} +7
In order to find the vertices, aka "turning points", we need to see around what area the graph will curve quickly from bottom-left to top-right. If the value being cubed (in the parentheses) is around -8, y will be close to 0, since -8+7=-1. (-2)^3 = -8. So x+5=-2, x=-7.
At x=-6, y = (-6+5)^3+7 = (-1)^3+7
y = -1+7 = 6
At x=-5, y = 0+7 = 7
Above x=-4, the y jumps rapidly above 10, and below x=-9, the y jumps rapidly below -50
What does all that mean???
That between x = -9 and x = -4 (x = -4,-5,-6,-7,-8,-9), the temperature (T(x) or y) does not change very much. Therefore, around those temperatures is a turning point, where the phase shift occurs from solid/liquid.
4 0
3 years ago
Which is equal to 8^-10/8^5 ?
makkiz [27]
8^{-10} can be converted into \frac{1}{ 8^{10} } , and applying this to 8^{-5} can see that

\frac{ \frac{1}{ 8^{10} } }{ \frac{1}{ 8^{5} } }

This gives us 

\frac{ 8^{5} }{ 8^{10} }  =  \frac{1}{ 8^{5} } = 8^{-5}
8 0
3 years ago
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