28.8 = 18x....divide both sides by 18, eliminating the 18 on the right side
28.8 / 18 = x
1.6 = x <==
So area=1/2 base times height
50=1/2 base times height
multiply both sides by 2
100=base times height
base=4height
100=4height times height
100=4height^2
divide 4
25=height^2
squarer root
5=height
subisute
base=4(5)
base=20
height=5
Answer:
0.025 grams
Step-by-step explanation:
The water in the stopcock has a volume of 25 mL initially, After that, the whole water was drained out. So we have:
Volume of drained water = (25 mL)(1 x 10⁻⁶ m³/1 mL)
Volume of drained water = 25 x 10⁻⁶ m³
Density of drained water = 1000 kg/m³
So, for the mass of drained water:
Density of drained water = Mass of drained water/Volume of drained water
Mass of drained water = (Density of drained water)(Volume of drained water)
Mass of drained water = (1000 kg/m³)(25 x 10⁻⁶ m³)
<u>Mass of drained water = 0.025 gram</u>
Density
Answer:
927 cubic inches
Step-by-step explanation:
The area of the octagonal base is ...
A = (1/2)Pa
where P is the perimeter, and 'a' is the apothem. Using the given numbers, the base area is ...
A = (1/2)(8·4)(4.83) = 77.28 . . . square inches
The volume of the prism is given by ...
V = Bh
where B represents the area of the base, and h is the height.
V = (77.28 in^2)(12 in) = 927.36 in^3
The volume of the prism is about 927 cubic inches.
Answer is B) JK=9 and KL=10
you subtract 7 from 26 to get 19
