Answer:
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The examination of a microscopic slice of an object with a petrological microscope in order to determine the source of the material, is known as thin-section analysis.
<h3>
What is thin section analysis?</h3>
The microscopic analysis of the content and structure of sediments is known as micromorphology, often known as thin-section analysis. Concepts of plasmic fabric and morphological traits and structures, which date from the early 1960s, were initially established in soil science.
<h3>
What makes petrography significant?</h3>
An essential tool for the fluid inclusion study is petrography. The fundamental purpose of petrography is to classify the fluid phases, such as monophase, biphase, or multiphase, and to deduce the relative chronology of the entrapment of fluid inclusions to determine whether it is primary, secondary, or pseudosecondary.
Learn more about the microscope with the help of the given link:
brainly.com/question/18661784
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Answer:
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Explanation:
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Answer:
Explanation:
The nucleus of an atom contains neutrons and protons bonded tightly together. The same chemical element can have a different number of neutrons and still be the same element.
Answer:
Tungsten is used for this experiment
Explanation:
This is a Thermal - equilibrium situation. we can use the equation.
Loss of Heat of the Metal = Gain of Heat by the Water
Q = mΔT
Q = heat
m = mass
ΔT = T₂ - T₁
T₂ = final temperature
T₁ = Initial temperature
Cp = Specific heat capacity
<u>Metal</u>
m = 83.8 g
T₂ = 50⁰C
T₁ = 600⁰C
Cp = 
<u>Water</u>
m = 75 g
T₂ = 50⁰C
T₁ = 30⁰C
Cp = 4.184 j.g⁻¹.⁰c⁻¹
⇒ - 83.8 x x (50 - 600) = 75 x 4.184 x (50 - 30)
⇒ = 
j.g⁻¹.⁰c⁻¹
We know specific heat capacity of Tungsten = 0.134 j.g⁻¹.⁰c⁻¹
So metal Tungsten used in this experiment
