Examining the given reaction:
Li2O + H2O ........> 2LiOH
we find that, 1 mole of Li2O is required to react with one mole of H2O in order to produce two moles of LiOH.
Therefore, the ration between the required Li2O and H2O is 1:1
Based on this, 2.2 moles of H2O (water) are required to react with 2.2 moles of Li2O
Answer:
paramagnetic
Explanation:
The complex ion is : [Cr(CN)₆]³⁻
Oxidation state of Cr in [Cr(CN)₆]³⁻ is:
x + (-1)6 = -3
x = +3
CN⁻ is a strong field ligand which can result in pairing of the electrons.
The electronic configuration of Cr is:
1s²2s²2p⁶3s²3p⁶3d⁵4s¹
The electronic configuration of Cr³⁺ is:
1s²2s²2p⁶3s²3p⁶3d³
<u>These 3 electrons will be singly present in the 3 degenerate t₂g orbitals and per Hund's rule, pairing will not occur in the same level energy orbitals. So , no. of unpaired electrons will be 3 and the complex will be paramagnetic.</u>
Given :
Moles of Na : 1.06
Moles of C : 0.528
Moles of O : 1.59
To Find :
The empirical formula of the compound.
Solution :
Dividing moles of each atom with the smallest one i.e 0.528 .
So,
Na : 1.06/0.528 = 2.007 ≈ 2
C : 0.528/0.528 = 1
O : 1.59/0.528 = 3.011 ≈ 3
Rounding all them to nearest integer, we will get the number of each atom in the empirical formula.
So, empirical formula is 
.
Hence, this is the required solution.
Elements are ordered from left to right, increasing atomic number as they go. The periodic table allows us to find out and predict things about elements that haven’t been discovered yet!
