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2 years ago

Can someone pls help with the first two fill in the blanks

Chemistry

1 answer:

Rufina [12.5K]2 years ago

3 0

Answer:

Subscripts are small numbers that tell us the number of each type of atom in a compound

If there is no number stated then it automatically means there is one atom present

Coefficients are big numbers in front of formulas that tell us we have more than 1 molecule present

Using the example of 2H₂O

The coefficient (2) multiplies the number of atoms of each element in this formula. For hydrogen 2 × 2 = 4 hydrogen atoms and 2 × 1 = 2 oxygen atoms

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1 year ago

An industrial chemist studying bleaching and sterilizing prepares several hypochlorite buffers. Find the pH of 0.200 M HClO and

stellarik [79]

Answer:

The pH is 7.54

Explanation:

The Henderson - Hasselbalch equation states that for a buffer solution which consists of a weak acid and its conjugate base, the buffer pH is given by:

pH $=pk_{a} +log(\frac{[conjugate base]}{[weakacid]})$

pkₐ is for the acid

In this case, the buffer hypochlorous acid HClO is a weak acid, and its conjugate base is the hypochlorite anion ClO⁻ is delivered to the solution via sodium hypochlorite NaClO .

NaCIO = 0.200 M

HCIO = 0.200 M

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7 0

2 years ago

NH3 is a weak base (Kb = 1.8 × 10–5) and so the salt NH4Cl acts as a weak acid. What is the pH of a solution that is 0.084 M in

kolbaska11 [484]

Answer is: pH of solution is 5,17.
Kb(NH₃) = 1,8·10⁻⁵.
c(NH₄Cl) = 0,084 M = 0,084 mol/L.
Chemical reaction: NH₄⁺ + H₂O → NH₃ + H₃O⁺.
Ka · Kb = 10⁻¹⁴.
Ka(NH₄⁺) = 10⁻¹⁴ ÷ 1,8·10⁻⁵.
Ka(NH₄⁺) = 5,55·10⁻¹⁰.
[H₃O⁺] = [NH₃] = x.
Ka(NH₄⁺) = [H₃O⁺] · [NH₃] ÷ [NH₄⁺].
5,55·10⁻¹⁰ = x² ÷ (0,084 M - x).
Solve quadratic equation: x = [H₃O⁺] = 6,8·10⁻⁶ M.
pH = -log[H₃O⁺].
pH = -log(6,8·10⁻⁶ M) = 5,17.

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2 years ago