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Arte-miy333 [17]
3 years ago
7

Científico que formuló 3 leyes de astronomía

Physics
1 answer:
s2008m [1.1K]3 years ago
4 0

Answer:

El astrónomo alemán Johannes Kepler

Explanation:

Primera Ley:

Los planetas giran alrededor del Sol siguiendo una trayectoria elíptica. El Sol se sitúa en uno de los focos de la elipse.

La excentricidad e de una elipse es una medida de lo alejado que se encuentran los focos del centro.

Pues bien, la mayoría de las órbitas planetarias tienen un valor muy pequeño de excentricidad, es decir e ≈ 0. Esto significa que, a nivel práctico, pueden considerarse círculos descentrados.

Segunda Ley:

La recta que une el planeta con el Sol barre áreas iguales en tiempos iguales.Para que esto se cumpla, la velocidad del planeta debe aumentar a medida que se acerque al Sol. Esto sugiere la presencia de una fuerza que permite al Sol atraer los planetas, tal y como descubrió Newton años más tarde.

Tercera ley de Kepler:

La tercera ley, también conocida como armónica o de los periodos, relaciona los periodos de los planetas, es decir, lo que tardan en completar una vuelta alrededor del Sol, con sus radios medios.

Para un planeta dado, el cuadrado de su periodo orbital es proporcional al cubo de su distancia media al Sol.

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Explanation:

It is known that energy balance relation is as follows.

           \Delta E_{system} = E_{in} - E_{out}

Also,   W_{in} = \Delta U

so,       W_{in} = mC_{v}(T_{2} - T_{1})  

According to the ideal gas equation,

           T_{2} = T_{1} \frac{P_{2}}{P_{1}}

Putting the values into the above equation as follows.

             T_{2} = T_{1} \frac{P_{2}}{P_{1}}

                         = (520R) \frac{40psia}{30psia}

                         = 693.3 R

Now, we will convert the temperature into degree Fahrenheit as follows.

            693.3 - 458.67

          = 234.63^{o}F

From table A-2E_{a}

 C_{p} = 0.240 Btu/lbm R  and   C_{v} = 0.171 Btu/lbm

Now, we will substitute the energy balance as follows.

            W_{in} = mC_{v}(T_{2} - T_{1})  

                         = 2 lbm \times 0.171 Btu/lbm R (693.3 - 520)

                         = 59.3 Btu

Thus, we can conclude that final temperature of air is 59.3 Btu.

6 0
4 years ago
Which data set has the largest range?
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Answer:

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Explanation:

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3 years ago
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At its lowest setting a centrifuge rotates with an angular speed of calculate the angular velocity
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No answer is possible until we know the number that belongs after the words "... angular speed of ".

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3 years ago
Hari drag a load of 60 kg along a distance of 12 metre what amount of work does he do also mention the type of work​
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Answer:

W = 7056  J

Explanation:

Given that,

Mass of a load, m = 60 kg

Distance moved, d = 12 m

We need to find the amount of work. The work done by an object is given by :

W = Fd

So,

W = mg×d

W = 60 kg × 9.8 m/s²×12 m

W = 7056  J

So, the amount of work done is 7056  J.

6 0
3 years ago
If a box of supplies is dropped from the cargo hold of an airplane travelling at an altitude of 4,410 meters how long will it ta
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Answer:

It will take 30 seconds to reach the ground, and it will be travelling at 294 m/s when it does so. This means that its average velocity was 147 m/s.

Explanation:

d=v_ot+\dfrac{1}{2}at^2

Since the initial velocity of a dropped object is 0, we can make this the equation:

d=\dfrac{1}{2}at^2 \\\\4410=\dfac{1}{2}(9.8)t^2 \\\\t^2=900

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The final velocity can be calculated with the formula:

v_f=v_o+at

Once again, since there is no initial velocity:

v_f=at \\\\v_f=(9.8)(30)=294m/s

Since the initial velocity is 0, the average vertical velocity is 294/2=147 m/s.

Hope this helps!

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3 years ago
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