Hi there!
We know that:
U = Potential Energy (J)
K = Kinetic Energy (J)
E = Total Energy (J)
At 10m, the total amount of energy is equivalent to:
U + K = 50 + 50 = 100 J
To find the highest point the object can travel, K = 0 J and U is at a maximum of 100 J, so:
100J = mgh
We know at 10m U = 50J, so we can solve for mass. Let g = 10 m/s².
50J = 10(10)m
m = 1/2 kg
Now, solve for height given that E = 100 J:
100J = 1/2(10)h
100J = 5h
<u>h = 20 meters</u>
Answer:
1st one
identity of the H₂O
When water (H2O) freezes into ice, some of the properties have changed but the identity of the H2O is the same. Explanation; Water can exist in liquid, solid; ice and gaseous state; steam. Freezing occurs when water is continuously cool until it turns to solid ice, water freezes at zero degree Celsius
Hope This Helps
The pH of the buffer solution is 7.30 for 0.172 m in Hypochlorous acid and 0.131 m in Sodium hypochlorite.
<h3>What is a buffer solution?</h3>
A weak acid and its conjugate base, or a weak base and its conjugate acid, are mixed together to form a solution called a buffer solution, which is based on water as the solvent. They do not change in pH when diluted or when modest amounts of acid or alkali are added to them. A relatively little amount of a strong acid or strong base has little effect on the pH of buffer solutions. As a result, they are employed to maintain a steady pH.
According to the question:
Ka = 3.8×10⁻⁸
pKa = - log (Ka)
= - log(3.8×10⁻⁸)
= 7.42
pH = pKa + log {[conjugate base]/[acid]}
= 7.42+ log {0.131/0.172}
= 7.302
To know more about buffer solutions, visit:
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A tornado is a natural force It is a very strong wind that causes thing to damage
Answer:
B = - 1.51 10⁻⁷ T
Explanation:
For this exercise we can use Faraday's law of induction
E = - 
In this case, they indicate that the normal and the magnetite field are in the same direction, so the angle is zero (cos 0 = 1), they give the area of the loop A = 4.32 10⁻⁴ m² and since we have N = 1470 turns in each one a voltage is induced
E = - N B A
B = -E A / N (1)
we find the induced voltage with ohm's law
V = i R
where the current is defined by
i = Q / t
we substitute
V = Q R / t
let's calculate
V = 9.18 10-3 56.0 / t
We must assume a time normally is t = 1 s
V = 0.514 V
this is the voltage in the circuit which must be the induced voltage V = E
we substitute in 1
B = - 0.514 4.32 10⁻⁴ / 1470
B = - 1.51 10⁻⁷ T
