I'm assuming A, but it says modern, so..
Answer:- A) 1 mole of Fe and 1.5 moles of 
.
Solution:- The balanced equation is:
From balanced equation, there is 1:3 mol ratio between 
and CO, From given data, 3 moles of and 1.5 moles of CO are taken for the reaction. CO is the limiting reactant as it's moles are less than the other reactant and which is also clear from the mole ratio. We could do the calculations also to support this. Let's calculate the moles of CO required to react completely with given 3 moles of .
= 9 mol CO
So, from calculations, 9 moles of CO are required to react completely with 3 moles of Iron(III)oxide but only 1.5 moles of CO are available. Hence, CO is the limiting reactant and the product moles are calculated from this as:
= 1 mol Fe
= 1.5 mol
So, the correct choice is A) 1 mole of Fe and 1.5 moles of .
Answer:
1461.7 g of AgI
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
CaI₂ + 2AgNO₃ —> 2AgI + Ca(NO₃)₂
From the balanced equation above,
1 mole of CaI₂ reacted to produce 2 moles of AgI.
Next, we shall determine the number of mole AgI produced by the reaction of 3.11 moles of CaI₂. This can be obtained as follow:
From the balanced equation above,
1 mole of CaI₂ reacted to produce 2 moles of AgI.
Therefore, 3.11 moles of CaI₂ will react to produce = 3.11 × 2 = 6.22 moles of AgI
Finally, we shall determine the mass of 6.22 moles of AgI. This can be obtained as follow:
Mole of AgI = 6.22 moles
Molar mass of AgI = 108 + 127
= 235 g/mol
Mass of AgI =?
Mass = mole × molar mass
Mass of AgI = 6.22 × 235
Mass of AgI = 1461.7 g
Therefore, 1461.7 g of AgI were obtained from the reaction.
Answer:
The temperature at which the vapor pressure of a liquid is just equal to the external ... The conversion of a liquid to a gas below the boiling point is called ... equilibrium temperature of the mixture was 36.0 °C. What is the specific heat (J/ g°C) of the metal
Explanation:
