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telo118 [61]
3 years ago
5

a flashlight has 6 batteries, 2 are defective. what is the probability you select at least 1 good battery

Mathematics
1 answer:
irga5000 [103]3 years ago
3 0

Answer:hhthfgh


Step-by-step explanation:

htrhghyrjyjytrhytrh

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Find the indicated function value for csc -450°
Mekhanik [1.2K]

Step-by-step explanation:

\csc( - 450 \degree) \\  \\  =  -  \csc450 \degree \\  \\  =  -  \csc(360 \degree + 90\degree) \\  \\  = -  \csc( 90\degree) \\  \\  =  - 1

4 0
3 years ago
One serving of rice has 44.9 grams of carbohydrates how many grams of carbohydrates de 2.5 servings of rice have
Fofino [41]

Answer:

112.25\ grams\ of\ carbohydrates    

Step-by-step explanation:

we know that

using proportion

\frac{1}{44.9}\frac{serving\ of\ rice}{grams\ of\ carbohydrates} =\frac{2.5}{x}\frac{serving\ of\ rice}{grams\ of\ carbohydrates} \\ \\x=44.9*2.5\\ \\x=112.25\ grams\ of\ carbohydrates

4 0
2 years ago
Find h, assuming the triangles formed are similar.
Eddi Din [679]

Answer:

h=18

Step-by-step explanation:

6 0
2 years ago
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Quadrilateral PONY is rotated 180° about the origin.
givi [52]

Answer:

Origin Rule: (x,y) to (kx,ky) where k is the scale factor.

180 degrees: (x,y) to (-x,-y)

Step-by-step explanation:

Rules are listed above.

3 0
2 years ago
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Two trains are 400 miles apart, and their speeds differ by 10 mph. They travel toward each other and meet in 4 hours. Find the s
Katen [24]
So.. the two trains, are 400 miles apart, their speeds differ by 10, so one train is faster than the other.. .let's say   train A is faster than train B, by 10mph

so if train A has a speed rate of "r", then B has a rate of "r - 10"

after train A has beeng running for 4hrs, it has travelled a distance "d"

train B has travelled also for 4hrs, they're both 400 miles apart, and travelling towards each other, so the total distance travelled by both is 400miles

so after 4hours B has travelled the slack from 400 and "d", namely 400 - d

recall your d = rt --> distance = rate * time

\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{Train A}&d&r&4\\
\textit{Train B}&400-d&r-10&4
\end{array}\\\\
-----------------------------\\\\

\begin{cases}
\boxed{d}=4r\\
400-d=(r-10)4\\
----------\\
400-\boxed{4r}=(r-10)4
\end{cases}

solve for "r", to find the speed of the faster train A

what's the speed of B? well, B's rate is r - 10
4 0
3 years ago
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