Question

3. Mr. Hogan in his 3000 kg truck is driving down

Answer 1

Answer:

$|I|=21,000\ kg.m/s$

Correct answer: Option E

Explanation:

Impulse and Momentum

The Impulse is defined as the change of momentum of an object in a certain interval. The formula is:

$I=\Delta p=p_f-p_o$

Where pf and po are the final and initial momentums respectively. Knowing that for m= mass of the object and v=velocity (or speed in the scalar form)

$p=m.v$

Thus

$I=m(v_f-v_o)$

Mr. Hogan's 3000 kg truck is initially at 36 m/s and later slows down to 29 m/s. We compute the impulse as follows

$I=3000\ kg(29\ m/s-36\ m/s)$

$I=3000(-7)\ kg.m/s$

$I=-21,000\ kg.m/s$

We are asked for the magnitude, thus

$|I|=21,000\ kg.m/s$

Correct Answer: Option E